P and Q are considering to apply for a job. The probability that P applies for the job is \(\frac{1}{4}\) , the probability that P applies for the job given that Q applies for the job is \(\frac{1}{2}\) , and the probability that Q applies for the job given that P applies for the job is \(\frac{1}{3}\) . Then the probability that P does not apply for the job given that Q does not apply for the job is
\(\frac{4}{5}\)
Let A and B denote applications by P and Q. P(A∩B)=P(A)P(B|A)=(1/4)(1/3)=1/12. Hence P(B)=(1/12)/(1/2)=1/6. P(A′∩B′)=1−[1/4+1/6−1/12]=2/3 and P(B′)=5/6. Therefore P(A′|B′)=(2/3)/(5/6)=4/5.
A box contains 5 coins: 4 regular coins and 1 fake coin. When a regular coin is tossed, the probability 𝑃(ℎ𝑒𝑎𝑑) = 0.5 and for a fake coin, 𝑃(ℎ𝑒𝑎𝑑) = 1. You pick a coin at random and toss it twice, and get two heads. The probability that the coin you have chosen is the fake coin is _______. (rounded off to two decimal places)