$\oplus \text { and } \odot \text { are two operators on numbers p and q such that}$ $p \odot q = p - q, \text{ and } p \oplus q = p \times q$ $\text{Then, } (9 \odot (6 \oplus 7)) \odot (7 \oplus (6 \odot 5))=$
The problem defines two operators:
We need to evaluate the expression: $(9 ⊙ (6 ⊕> 7)) ⊙ (7 ⊕> (6 ⊙ 5))$
First, calculate the value inside the first main parenthesis: $(9 ⊙ (6 ⊕> 7))$
So, the left side evaluates to -33.
Next, calculate the value inside the second main parenthesis: $(7 ⊕> (6 ⊙ 5))$
So, the right side evaluates to 7.
Now, combine the results of the left and right sides using the main $⊙$ operator:
The final result of the expression is -40.
In an engineering college of 10,000 students, 1,500 like neither their core branches nor other branches. The number of students who like their core branches is 1/4th of the number of students who like other branches. The number of students who like both their core and other branches is 500.
The number of students who like their core branches is
$A$ is an ($n \times n$) matrix. Consider the following two statements
Statement 1: Columns of matrix $A$ are linearly independent
Statement 2: Inverse of matrix $A$ exists
Which one of the following statements is TRUE?