$\oplus \text { and } \odot \text { are two operators on numbers p and q such that}$ $p \odot q = p - q, \text{ and } p \oplus q = p \times q$ $\text{Then, } (9 \odot (6 \oplus 7)) \odot (7 \oplus (6 \odot 5))=$
The problem defines two operators:
We need to evaluate the expression: $(9 ⊙ (6 ⊕> 7)) ⊙ (7 ⊕> (6 ⊙ 5))$
First, calculate the value inside the first main parenthesis: $(9 ⊙ (6 ⊕> 7))$
So, the left side evaluates to -33.
Next, calculate the value inside the second main parenthesis: $(7 ⊕> (6 ⊙ 5))$
So, the right side evaluates to 7.
Now, combine the results of the left and right sides using the main $⊙$ operator:
The final result of the expression is -40.
$A$ is an ($n \times n$) matrix. Consider the following two statements
Statement 1: Columns of matrix $A$ are linearly independent
Statement 2: Inverse of matrix $A$ exists
Which one of the following statements is TRUE?