One side of a rectangle is 12 m and its diagonal is 13 m. Find its area ?
60 sq.m
The problem asks us to find the area of a rectangle given the length of one side and the length of its diagonal. We are given that one side is 12 m and the diagonal is 13 m.
A rectangle has four interior angles, each measuring 90 degrees. When a diagonal is drawn across a rectangle, it divides the rectangle into two right-angled triangles. The sides of the rectangle form the legs of these right-angled triangles, and the diagonal acts as the hypotenuse.
In this specific problem, we have a right-angled triangle with one leg measuring 12 m (the given side of the rectangle) and the hypotenuse measuring 13 m (the diagonal). Let the other side of the rectangle (the unknown side, which is the other leg of the right-angled triangle) be denoted by $x$ meters.
We can use the Pythagorean theorem to find the length of the unknown side. The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides (the legs). Mathematically, this is represented as:
$\text{leg}_1^2 + \text{leg}_2^2 = \text{hypotenuse}^2$
Substituting the given values into the theorem, we get:
$12^2 + x^2 = 13^2$
Now, let's solve for $x$:
$144 + x^2 = 169$
Subtract 144 from both sides:
$x^2 = 169 - 144$
$x^2 = 25$
Take the square root of both sides:
$x = \sqrt{25}$
$x = 5$
So, the lengths of the sides of the rectangle are 12 m and 5 m.
The area of a rectangle is calculated by multiplying its length by its width:
Area = Length $\times$ Width
Area = 12 m $\times$ 5 m
Area = 60 square meters (sq. m)
Now let's compare our calculated area with the given options:
Our calculated area is 60 sq. m, which matches Option 1.
Therefore, the area of the rectangle is 60 sq.m.
| Concept | Description | Formula/Property |
|---|---|---|
| Rectangle Properties | Four sides, four right (90°) angles, opposite sides are equal and parallel. | Each interior angle = 90°. Opposite sides equal. |
| Pythagorean Theorem | In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides (legs). | $a^2 + b^2 = c^2$, where $a$ and $b$ are legs, $c$ is hypotenuse. |
| Area of Rectangle | The space enclosed within the boundaries of the rectangle. | Area = Length $\times$ Width |
| Diagonal of Rectangle | A line segment connecting opposite vertices. It forms a right-angled triangle with two adjacent sides. | Diagonal length ${}^2$ = Length${}^2$ + Width${}^2$ (by Pythagorean theorem) |
Understanding the properties of geometric shapes like rectangles is fundamental in geometry. The relationship between the sides and the diagonal through the Pythagorean theorem is a common application.
Problems involving rectangles and diagonals often require the use of the Pythagorean theorem, making it a crucial tool in solving such geometry questions.
If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:
The width of the path around a square field is 4.5 m and its area is 105.75 m 2. Find the cost of fencing the field at the rate of Rs. 100 per meter.
What is the area of the square (in cm 2) whose vertices lie on a circle of radius 5 cm?
The circumcentre of an equilateral triangle is at a distance of 3.2 cm from the base of the triangle. What is the length (in cm) of each of its altitudes?
The perimeter of a circular lawn is 1232 m. There is 7 m wide path around the lawn. The area (in m 2) of the path is:
Take \(\left(\pi=\frac{22}{7}\right)\)