A can X contains 399 litres of petrol and a can Y contains 532 litres of diesel. They are to be
bottled in bottles of equal size so that whole of petrol and diesel would be separately bottled.
The bottle capacity in terms of litres is an integer. How many different bottle sizes are possible?
4
The problem asks us to find the number of different possible bottle sizes, in litres, that can be used to bottle 399 litres of petrol and 532 litres of diesel separately, with the bottle capacity being an integer. This means the bottle size must be a factor (or divisor) of 399 and also a factor of 532. In other words, the bottle size must be a common divisor of 399 and 532.
The common divisors of two numbers are exactly the divisors of their Greatest Common Divisor (GCD). Therefore, to find all possible bottle sizes, we first need to calculate the GCD of 399 and 532. Once we find the GCD, the number of its divisors will give us the number of possible bottle sizes.
We can find the GCD by using prime factorization:
Now, let's find the common prime factors and their lowest powers:
The GCD is the product of these common prime factors raised to their lowest powers:
$\text{GCD}(399, 532) = 7^1 \times 19^1 = 7 \times 19 = 133$.
The GCD of 399 and 532 is 133.
The possible bottle sizes are the divisors of the GCD, which is 133. Let's list the divisors of 133:
The divisors of 133 are 1, 7, 19, and 133.
We found that the possible bottle sizes are 1 litre, 7 litres, 19 litres, and 133 litres. There are a total of 4 possible different bottle sizes.
| Quantity (Litres) | Possible Bottle Sizes (Litres) |
|---|---|
| 399 (Petrol) | Common Divisors of 399 and 532 (Divisors of GCD(399, 532)) |
| 532 (Diesel) | |
| GCD(399, 532) | 133 |
| Divisors of 133 | 1, 7, 19, 133 |
| Number of Possible Sizes | 4 |
Therefore, there are 4 different possible bottle sizes that can be used.
| Concept | Explanation | Relevance to Problem |
|---|---|---|
| Divisor (Factor) | A number that divides another number exactly, with no remainder. | The bottle size must be a divisor of both 399 and 532. |
| Common Divisor | A number that is a divisor of two or more numbers. | The bottle size must be a common divisor of 399 and 532. |
| Greatest Common Divisor (GCD) | The largest positive integer that divides two or more integers without leaving a remainder. | The set of common divisors of two numbers is the same as the set of divisors of their GCD. |
| Prime Factorization | Expressing a composite number as a product of its prime factors. | Useful method for finding the GCD of two numbers. |
The concept of GCD is fundamental in number theory. The GCD of two numbers represents the largest possible size of a unit that can perfectly measure both quantities. In this problem, the GCD (133 litres) is the largest possible bottle size that can perfectly bottle both the petrol and the diesel without any leftovers.
Any smaller bottle size that can also perfectly bottle both quantities must also be a divisor of this largest possible size (the GCD). That's why the possible bottle sizes are the divisors of the GCD. If a number $d$ divides both $a$ and $b$, then $d$ must also divide $\text{GCD}(a, b)$. Conversely, every divisor of $\text{GCD}(a, b)$ divides both $a$ and $b$. This property is crucial for solving problems like this one.
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