This solution explains how to find the time needed for an amount to triple under simple interest, given the time it takes to double.
Simple Interest is a method of calculating the interest charge on a loan. It is determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments.
The formula for Simple Interest (SI) is:
$ SI = \frac{P \times R \times T}{100} $
Where:
The total Amount ($A$) after time $T$ is the sum of the Principal and the Simple Interest:
$ A = P + SI $
The problem states:
When the amount doubles, the final amount $A = 2P$. This means the interest earned ($SI$) is equal to the principal amount:
$ SI = A - P = 2P - P = P $
We know this takes 10 years ($T = 10$). So, earning interest equal to the principal takes 10 years.
Using the simple interest formula with $SI = P$ and $T = 10$ years:
$ P = \frac{P \times R \times 10}{100} $
We can cancel $P$ from both sides (assuming $P \neq 0$):
$ 1 = \frac{R \times 10}{100} $
Now, solve for $R$:
$ 1 = \frac{R}{10} $
$ R = 1 \times 10 = 10\% $
So, the fixed rate of simple interest is 10% per year.
We want to find the time ($T_2$) when the amount triples. If the initial amount is $P$, the final amount $A = 3P$. The interest earned ($SI$) required for this is:
$ SI = A - P = 3P - P = 2P $
So, we need to earn interest equal to twice the principal amount.
Using the simple interest formula with $SI = 2P$ and the calculated rate $R = 10\%$:
$ 2P = \frac{P \times 10 \times T_2}{100} $
Cancel $P$ from both sides:
$ 2 = \frac{10 \times T_2}{100} $
Simplify the right side:
$ 2 = \frac{T_2}{10} $
Solve for $T_2$:
$ T_2 = 2 \times 10 = 20 $
Therefore, it will take 20 years for the amount to triple.
Simple Interest implies that the interest earned is the same every year.
This method confirms the result obtained using the formulas.
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