Match List I with List II: Choose the correct answer from the options given below:List I List II (A) Transforming principle (I) Jacob and Monod (B) Replication of DNA (II) Frederick Griffith (C) Lac operon concept (III) Alec Jeffreys (D) DNA Fingerprinting (IV) Watson and Crick
(b) A-II, B-IV, C-I, D-III
This question asks us to match significant discoveries and concepts in the field of biology, particularly genetics and molecular biology, with the scientists who are credited with them. To answer this, we need to recall the key contributions of each scientist listed.
Let's analyze each item in List I and find its corresponding match in List II:
Based on the analysis, the correct matches are:
This gives us the sequence A-II, B-IV, C-I, D-III.
| Discovery/Concept (List I) | Scientist(s) (List II) | Matching Pair |
|---|---|---|
| (A) Transforming principle | (II) Frederick Griffith | A-II |
| (B) Replication of DNA (Structural basis) | (IV) Watson and Crick | B-IV |
| (C) Lac operon concept | (I) Jacob and Monod | C-I |
| (D) DNA Fingerprinting | (III) Alec Jeffreys | D-III |
The topics covered in this question are fundamental to genetics and molecular biology. Let's delve a little deeper into some related concepts:
Frederick Griffith's experiment involved injecting mice with different strains of *Streptococcus pneumoniae*. The 'S' strain (smooth) was virulent, while the 'R' strain (rough) was non-virulent. Heat-killed S strain was also non-virulent. However, when a mixture of heat-killed S strain and live R strain was injected, the mice died, and live S strain bacteria were recovered. This showed that some substance from the heat-killed S strain had 'transformed' the live R strain into the virulent S strain. Oswald Avery, Colin MacLeod, and Maclyn McCarty later identified DNA as this transforming principle in 1944.
The Watson and Crick model of the DNA double helix suggested that each strand could serve as a template for synthesizing a new complementary strand. This semi-conservative model was experimentally proven by Meselson and Stahl in 1958 using isotopes of nitrogen. DNA replication is a complex process involving many enzymes like DNA polymerase, helicase, ligase, etc.
An operon is a functional unit of DNA that contains a cluster of genes under the control of a single promoter. It includes structural genes (coding for proteins), a promoter (where RNA polymerase binds), an operator (a regulatory region), and sometimes a regulator gene (coding for a repressor or activator protein). The lac operon is an inducible operon, meaning it is typically off but can be turned on in the presence of lactose. This is a key example of how gene expression is regulated in prokaryotes.
DNA fingerprinting (also known as DNA profiling) exploits variations in repetitive DNA sequences, such as Variable Number Tandem Repeats (VNTRs) or Short Tandem Repeats (STRs), between individuals. Since these patterns are highly variable, they can be used for identification. Applications include forensic science (identifying suspects or victims), paternity testing, identifying remains, and studying genetic diversity.
What will be the chromosome number in the gamete of fruit fly if its meiocyte has 8 chromosomes?
Match List-I with List-II:
| List-I (Organism) | List-II (Sex Chromosomes) |
|---|---|
| (A) Male grasshopper | (I) XY |
| (B) Male Drosophila | (II) XX |
| (C) Female bird | (III) XX |
| (D) Female grasshopper | (IV) XO |
Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Bacteriophage lambda | (I) 231 gene |
| (B) Y-chromosome of human | (II) 48502 bp |
| (C) Haploid content of human DNA | (III) 3.3 × 109 bp |
| (D) Escherichia coli DNA | (IV) 4.6 × 106 bp |
Choose the correct answer from the options given below:
Central dogma in molecular biology states that genetic information flows from:
Read the following and select the set of correct statements. (A) Euchromatin is transcriptionally inactive (B) Heterochromatin is more densely packed (C) Heterochromatin is loosely packed (D) Euchromatin is transcriptionally active (E) Euchromatin stains lighter