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Question

Mass of an object on earth is 12. What is its weight on moon?

The correct answer is

19.6

Understanding Mass and Weight

In physics, mass and weight are two distinct concepts, though they are often used interchangeably in everyday language. It is crucial to understand their differences when dealing with problems involving gravity.

  • Mass: Mass is a fundamental measure of the amount of matter in an object. It is an intrinsic property of an object and does not change with location. For example, an object's mass remains the same whether it is on Earth, on the Moon, or in space. Mass is typically measured in kilograms (kg).
  • Weight: Weight, on the other hand, is the force of gravity acting on an object's mass. It depends on both the mass of the object and the acceleration due to gravity at its current location. Weight is a force, and like all forces, it is measured in Newtons (N). The formula for weight is: \[ W = mg \] Where \(W\) is weight, \(m\) is mass, and \(g\) is the acceleration due to gravity.

Gravity on Earth and Moon

The acceleration due to gravity varies depending on the celestial body. For Earth, the approximate acceleration due to gravity (\(g_E\)) is \(9.8 \text{ m/s}^2\). The Moon has a much weaker gravitational pull than Earth. The acceleration due to gravity on the Moon (\(g_M\)) is approximately one-sixth of that on Earth.

So, we can write the relationship as: \[ g_M = \frac{g_E}{6} \]

Using the standard value for Earth's gravity, we calculate Moon's gravity:

\[ g_M = \frac{9.8 \text{ m/s}^2}{6} \approx 1.633 \text{ m/s}^2 \]

Calculating Object Weight on Moon

The problem states that the mass of an object on Earth is 12. Since mass is an intrinsic property and does not change with location, the mass of the object on the Moon will also be 12 kg (assuming the unit is kilograms as is standard for mass in such problems).

Given:

  • Mass of the object (\(m\)) = 12 kg
  • Acceleration due to gravity on Earth (\(g_E\)) = \(9.8 \text{ m/s}^2\)

First, we determine the acceleration due to gravity on the Moon:

\[ g_M = \frac{g_E}{6} = \frac{9.8 \text{ m/s}^2}{6} \]

Now, we can calculate the weight of the object on the Moon using the formula \(W = mg\):

\[ W_{\text{Moon}} = m \times g_M \] \[ W_{\text{Moon}} = 12 \text{ kg} \times \left( \frac{9.8 \text{ m/s}^2}{6} \right) \]

We can simplify the expression before multiplying:

\[ W_{\text{Moon}} = \frac{12}{6} \times 9.8 \text{ N} \] \[ W_{\text{Moon}} = 2 \times 9.8 \text{ N} \] \[ W_{\text{Moon}} = 19.6 \text{ N} \]

Therefore, the weight of the object on the Moon is 19.6 Newtons.

Summary of Key Values for Object Weight Calculation

Concept Value Unit
Mass of object 12 kg
Acceleration due to gravity on Earth (\(g_E\)) 9.8 m/s\(^2\)
Acceleration due to gravity on Moon (\(g_M\)) \( \frac{9.8}{6} \approx 1.633 \) m/s\(^2\)
Weight of object on Moon 19.6 N

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Important Questions from Acceleration due to gravity of the earth

  1. If a ball is thrown vertically upwards with the speed $u$, the distance covered during the second-to-last $t$ seconds of its ascent is
    (Assume $t$ is less than half of the total ascent time).
  2. A body freely falling from rest has acquired a velocity ‘v’ after it falls through a distance ‘h’. The distance it has to fall down further for its velocity to become double is:

  3. On earth, the value of G = 6.67 × 10 -11  Nm 2kg -2 . What is the value on moon, where acceleration due to gravity is nearly one - sixth than that of earth?

  4. What is the force required to produce an acceleration of 9.8 m/s 2on a body of weight 9.8N? Take g = 9.8 m/s 2.

  5. At what height above the surface of the earth does the weight of an object reduce by 1%. Given the radius of the earth is 6400.

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