Mass of an object on earth is 12. What is its weight on moon?
19.6
In physics, mass and weight are two distinct concepts, though they are often used interchangeably in everyday language. It is crucial to understand their differences when dealing with problems involving gravity.
The acceleration due to gravity varies depending on the celestial body. For Earth, the approximate acceleration due to gravity (\(g_E\)) is \(9.8 \text{ m/s}^2\). The Moon has a much weaker gravitational pull than Earth. The acceleration due to gravity on the Moon (\(g_M\)) is approximately one-sixth of that on Earth.
So, we can write the relationship as: \[ g_M = \frac{g_E}{6} \]
Using the standard value for Earth's gravity, we calculate Moon's gravity:
\[ g_M = \frac{9.8 \text{ m/s}^2}{6} \approx 1.633 \text{ m/s}^2 \]The problem states that the mass of an object on Earth is 12. Since mass is an intrinsic property and does not change with location, the mass of the object on the Moon will also be 12 kg (assuming the unit is kilograms as is standard for mass in such problems).
Given:
First, we determine the acceleration due to gravity on the Moon:
\[ g_M = \frac{g_E}{6} = \frac{9.8 \text{ m/s}^2}{6} \]Now, we can calculate the weight of the object on the Moon using the formula \(W = mg\):
\[ W_{\text{Moon}} = m \times g_M \] \[ W_{\text{Moon}} = 12 \text{ kg} \times \left( \frac{9.8 \text{ m/s}^2}{6} \right) \]We can simplify the expression before multiplying:
\[ W_{\text{Moon}} = \frac{12}{6} \times 9.8 \text{ N} \] \[ W_{\text{Moon}} = 2 \times 9.8 \text{ N} \] \[ W_{\text{Moon}} = 19.6 \text{ N} \]Therefore, the weight of the object on the Moon is 19.6 Newtons.
| Concept | Value | Unit |
|---|---|---|
| Mass of object | 12 | kg |
| Acceleration due to gravity on Earth (\(g_E\)) | 9.8 | m/s\(^2\) |
| Acceleration due to gravity on Moon (\(g_M\)) | \( \frac{9.8}{6} \approx 1.633 \) | m/s\(^2\) |
| Weight of object on Moon | 19.6 | N |
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