On earth, the value of G = 6.67 × 10 -11 Nm 2kg -2 . What is the value on moon, where acceleration due to gravity is nearly one - sixth than that of earth?
6.67 × 10 -11 Nm 2kg -2
The question asks for the value of the gravitational constant (G) on the Moon, given its value on Earth and the relationship between acceleration due to gravity on the Earth and the Moon.
Let's break down the key concepts involved:
$$F = G \frac{m_1 m_2}{r^2}$$
$$g = \frac{GM}{R^2}$$
The question states that the acceleration due to gravity on the Moon is nearly one-sixth than that of Earth ($g_{moon} \approx \frac{1}{6} g_{earth}$). This fact is correct, but it relates to 'g', not 'G'.
The crucial point to understand is the difference between 'G' and 'g'.
The value of G on Earth is given as $6.67 \times 10^{-11} \text{ Nm}^2\text{kg}^{-2}$. Since G is a universal constant, its value does not change when you go from Earth to the Moon, or anywhere else in the universe.
Therefore, the value of the gravitational constant G on the Moon is exactly the same as its value on Earth.
The value of G on the Moon is $6.67 \times 10^{-11} \text{ Nm}^2\text{kg}^{-2}$.
Let's compare this with the given options:
Option 3 matches the calculated value based on the understanding that G is a universal constant.
It is important not to confuse G and g. Here's a summary:
| Feature | Gravitational Constant (G) | Acceleration due to gravity (g) |
|---|---|---|
| Nature | Universal Constant | Depends on celestial body (variable) |
| Value on Earth | $6.67 \times 10^{-11} \text{ Nm}^2\text{kg}^{-2}$ | Approximately $9.8 \text{ m/s}^2$ |
| Value on Moon | $6.67 \times 10^{-11} \text{ Nm}^2\text{kg}^{-2}$ (Same as Earth) | Approximately $1.62 \text{ m/s}^2$ (About 1/6th of Earth's g) |
| Involved in | Newton's Law of Universal Gravitation ($F = G \frac{m_1 m_2}{r^2}$) | Force on an object due to gravity ($F = mg$) or motion under gravity |
The fact that $g_{moon}$ is different from $g_{earth}$ is due to the Moon having a different mass and radius compared to Earth. This does not affect the fundamental constant G.
Therefore, the value of G remains constant.
| Concept | Symbol | Nature | Approximate Value (Earth) |
|---|---|---|---|
| Gravitational Constant | G | Universal Constant | $6.67 \times 10^{-11} \text{ Nm}^2\text{kg}^{-2}$ |
| Acceleration due to gravity | g | Variable (depends on location) | $9.8 \text{ m/s}^2$ |
The value of the gravitational constant G was first experimentally determined by Henry Cavendish in 1798 using a torsion balance. His experiment provided the first accurate measurement of G, which in turn allowed the calculation of the Earth's mass.
The constant G is one of the fundamental constants of nature. Its precise value is important in many areas of physics and astronomy, including calculating the mass of planets and stars, understanding the motion of celestial bodies, and studying cosmology.
Despite being a fundamental constant, G is one of the least precisely known fundamental constants, mainly due to the weakness of the gravitational force between laboratory-sized objects.
Understanding that G is universal is key to solving problems involving gravity in different locations in space.
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