Let $Y = Z^2$, $Z = \frac{X - \mu}{\sigma}$, where $X$ is a normal random variable with mean $\mu$ and variance $\sigma^2$. The variance of $Y$ is
We are given a normal random variable $X$ with mean $\mu$ and variance $\sigma^2$, denoted as $X \sim N(\mu, \sigma^2)$.
A standardized variable $Z$ is defined as $Z = \frac{X - \mu}{\sigma}$. This transformation makes $Z$ a standard normal random variable, meaning $Z \sim N(0, 1)$.
We need to find the variance of $Y = Z^2$.
The variable $Y$ is defined as $Y = Z^2$. Since $Z \sim N(0, 1)$, the square of $Z$, which is $Z^2$, follows a Chi-squared distribution with 1 degree of freedom. This is denoted as $Y \sim \chi^2(1)$.
The variance of a Chi-squared distribution with $k$ degrees of freedom ($\chi^2(k)$) is given by the formula $Var = 2k$.
In our case, $Y \sim \chi^2(1)$, so $k=1$. Applying the formula:
$ Var(Y) = 2k = 2 \times 1 = 2 $
Therefore, the variance of $Y$ is 2.
Let $X$ and $Y$ be continuous random variables with probability density functions $P_X(x)$ and $P_Y(y)$, respectively. Further, let $Y = X^2$ and $P_X(x) = \begin{cases} 1, & x\in (0,1] \\ 0, & \text{otherwise} \end{cases}$
Which one of the following options is correct?
Consider a discrete random variable X whose probabilities are given below. The standard deviation of the random variable is ________ (round off to one decimal place).
| $x_1$ | 1 | 2 | 3 | 4 |
| $P(X = x_i)$ | 0.3 | 0.1 | 0.3 | 0.3 |
If $X$ is a continuous random variable with the probability density function
$f(x) = \begin{cases} \frac{K}{4}, & 0 \le x \le 1 \\ 0, & \text{otherwise} \end{cases}$
then the value of $K$ is __________. (Answer in integer)