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Question

Let $X$ be a random variable that follows $Uniform(-1, 1)$ distribution. The conditional distribution of the random variable $Y$ given $X = x$ is the $Uniform(x^2 - 0.1, x^2 + 0.1)$ distribution.

The value of $correlation(X, Y)$ is __________ . (Answer in integer)

We need to find the correlation between random variables $X$ and $Y$, denoted as $Corr(X, Y)$.

Understanding Random Variable Distributions

  • $X$ follows a $Uniform(-1, 1)$ distribution.
  • The conditional distribution of $Y$ given $X=x$ is $Uniform(x^2 - 0.1, x^2 + 0.1)$.

Calculating Expected Values

First, let's find the expected value of $X$ and $Y$ given $X=x$.

  • For $X \sim Uniform(a, b)$, the expected value is $E[X] = \frac{a+b}{2}$.
    So, $E[X] = \frac{-1 + 1}{2} = 0$.
  • For $Y|X=x \sim Uniform(x^2 - 0.1, x^2 + 0.1)$, the conditional expectation is: $E[Y|X=x] = \frac{(x^2 - 0.1) + (x^2 + 0.1)}{2} = \frac{2x^2}{2} = x^2$.

Calculating Overall Expected Value E[Y]

Using the law of total expectation, $E[Y] = E[E[Y|X]]$:

$E[Y] = E[X^2]$

For $X \sim Uniform(a, b)$, $E[X^2] = \frac{a^2 + ab + b^2}{3}$.
Here, $a = -1$ and $b = 1$.
$E[X^2] = \frac{(-1)^2 + (-1)(1) + (1)^2}{3} = \frac{1 - 1 + 1}{3} = \frac{1}{3}$.
Therefore, $E[Y] = \frac{1}{3}$.

Calculating Covariance Cov(X, Y)

The formula for covariance is $Cov(X, Y) = E[XY] - E[X]E[Y]$.

We need $E[XY]$. Using the law of total expectation again:

$E[XY] = E[E[XY|X]] = E[X \cdot E[Y|X]]$

Substitute $E[Y|X] = X^2$:
$E[XY] = E[X \cdot X^2] = E[X^3]$.

For $X \sim Uniform(-1, 1)$, $E[X^k] = \frac{1}{1 - (-1)} \int_{-1}^{1} x^k dx$.

Calculate $E[X^3]$:
$E[X^3] = \frac{1}{2} \int_{-1}^{1} x^3 dx = \frac{1}{2} \left[ \frac{x^4}{4} \right]_{-1}^{1} = \frac{1}{2} \left( \frac{1^4}{4} - \frac{(-1)^4}{4} \right) = \frac{1}{2} \left( \frac{1}{4} - \frac{1}{4} \right) = 0$.
So, $E[XY] = 0$.

Now, calculate the covariance:
$Cov(X, Y) = E[XY] - E[X]E[Y] = 0 - (0) \cdot (\frac{1}{3}) = 0$.

Calculating Correlation Corr(X, Y)

The correlation is calculated as $Corr(X, Y) = \frac{Cov(X, Y)}{\sqrt{Var(X) Var(Y)}}$.

Since $Cov(X, Y) = 0$, and the variances $Var(X)$ and $Var(Y)$ are finite and non-zero (specifically $Var(X) = \frac{(1-(-1))^2}{12} = \frac{4}{12} = \frac{1}{3}$), the correlation is:

$Corr(X, Y) = \frac{0}{\sqrt{Var(X) Var(Y)}} = 0$.

Final Answer

The value of $correlation(X, Y)$ is 0.

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Important Questions from Correlation Analysis

  1. The value of simple correlation coefficient lies in the interval:

  2. Which option is correct for the correlation ratio E 2?

  3. Let θ be the angle made by the line of regression of Y on X. If σ Y= 2σ X and the correlation coefficient between X and Y is 0.3, the value θ equals

  4. The multiple correlation coefficient R 1,23 as compared to any simple correlation coefficients between the distinct variable X 1 ,X 2, and X 3is

  5. The coefficients of the regression β X|y and β Y|x , are known, The coefficient of correlation equals: 

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