31
The question asks for the greatest number, denoted as N, that divides 600, 631, and 724, ensuring the remainder is identical for each division.
A key principle states that if a number N divides multiple numbers (say A, B, C) leaving the same remainder, then N must perfectly divide the differences between these numbers (A-B, B-C, A-C). We first calculate these differences:
The greatest number N we are looking for is the Highest Common Factor (HCF) of these calculated differences: \(31\), \(93\), and \(124\).
To find the HCF, we list the prime factors for each difference:
By comparing the factors, we see that \(31\) is the only common factor present in all three numbers. Therefore, the HCF(\(31\), \(93\), \(124\)) is \(31\).
The HCF represents the greatest number N that satisfies the condition.
Thus, the value of N is \(31\).
The greatest three-digit number which is divisible by 14, 28, and 42 is:
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