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Question

Initially, the population of a town was 80,000 and increases at the rate of R%. If the population becomes 1,06,480 after three years, then the value of R is:

The correct answer is
10

Population Growth Rate Calculation

This problem involves calculating the annual rate of population increase (R%) over a period of three years, given the initial and final populations. We can solve this using the compound growth formula.

Understanding the Compound Growth Formula

The formula for compound growth is:

$ P_n = P_0 \left(1 + \frac{R}{100}\right)^n $

Where:

  • $P_n$ is the population after $n$ years.
  • $P_0$ is the initial population.
  • $R$ is the annual growth rate in percent.
  • $n$ is the number of years.

Applying the Formula to the Problem

From the question, we have:

  • Initial population, $P_0 = 80,000$
  • Population after 3 years, $P_3 = 1,06,480$
  • Number of years, $n = 3$
  • Annual growth rate = $R\%$

Step-by-Step Calculation

  1. Substitute the known values into the formula:

    $ 1,06,480 = 80,000 \left(1 + \frac{R}{100}\right)^3 $

  2. Isolate the growth factor term:

    Divide both sides by the initial population (80,000):

    $ \frac{1,06,480}{80,000} = \left(1 + \frac{R}{100}\right)^3 $

    $ 1.331 = \left(1 + \frac{R}{100}\right)^3 $

  3. Find the cube root of both sides:

    To find the value of $\left(1 + \frac{R}{100}\right)$, we take the cube root of 1.331:

    $ \sqrt[3]{1.331} = 1 + \frac{R}{100} $

    Since $1.1 \times 1.1 \times 1.1 = 1.331$, the cube root of 1.331 is 1.1.

    $ 1.1 = 1 + \frac{R}{100} $

  4. Solve for R:

    Subtract 1 from both sides:

    $ 1.1 - 1 = \frac{R}{100} $

    $ 0.1 = \frac{R}{100} $

    Multiply both sides by 100:

    $ R = 0.1 \times 100 $

    $ R = 10 $

Conclusion

The value of R, representing the annual population growth rate, is 10%.

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Important Questions from Percentage (Notes)

  1. 20% of a number is more than 20% of 620 by 210. The number is:
  2. Girish scored 572 marks in an examination and was 30 marks short of 28% of maximum marks. In the same examination, his friend scored 473 marks. What is the percentage of marks scored by his friend?
  3. Anubhav spent 14% of his income on electricity bills, 28% on rent and 18% on shopping. If $\frac{1}{4}$ th of the remaining amount is ₹5120, how much did he spend on electricity bills ?
  4. The total population of a town is 50,000. The number of males and females increases by 10% and 15% respectively and consequently the population of the town becomes 56,000. What was the number of males in the town?
  5. There is an increase of 30% in the number of people coming to a theatre after reducing the entry fee by 25% per person. How much change is expected in the total earnings?
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