This problem involves calculating the annual rate of population increase (R%) over a period of three years, given the initial and final populations. We can solve this using the compound growth formula.
The formula for compound growth is:
$ P_n = P_0 \left(1 + \frac{R}{100}\right)^n $
Where:
From the question, we have:
$ 1,06,480 = 80,000 \left(1 + \frac{R}{100}\right)^3 $
Divide both sides by the initial population (80,000):
$ \frac{1,06,480}{80,000} = \left(1 + \frac{R}{100}\right)^3 $
$ 1.331 = \left(1 + \frac{R}{100}\right)^3 $
To find the value of $\left(1 + \frac{R}{100}\right)$, we take the cube root of 1.331:
$ \sqrt[3]{1.331} = 1 + \frac{R}{100} $
Since $1.1 \times 1.1 \times 1.1 = 1.331$, the cube root of 1.331 is 1.1.
$ 1.1 = 1 + \frac{R}{100} $
Subtract 1 from both sides:
$ 1.1 - 1 = \frac{R}{100} $
$ 0.1 = \frac{R}{100} $
Multiply both sides by 100:
$ R = 0.1 \times 100 $
$ R = 10 $
The value of R, representing the annual population growth rate, is 10%.