Let the maximum marks for the examination be denoted by M.
Girish scored 572 marks.
This score was 30 marks less than 28% of the maximum marks.
This means that 28% of the maximum marks is equal to Girish's score plus the deficit:
$ 0.28 \times M = 572 + 30 $
$ 0.28 \times M = 602 $
To find the maximum marks M, we rearrange the equation:
$ M = \frac{602}{0.28} $
$ M = \frac{60200}{28} $
$ M = 2150 $
So, the maximum marks for the examination were 2150.
Girish's friend scored 473 marks.
The maximum marks are 2150.
To find the percentage of marks scored by the friend, we use the formula:
$ \text{Percentage} = \left( \frac{\text{Score Obtained}}{\text{Maximum Marks}} \right) \times 100 $
Substituting the values:
$ \text{Friend's Percentage} = \left( \frac{473}{2150} \right) \times 100 $
$ \text{Friend's Percentage} = \frac{47300}{2150} $
$ \text{Friend's Percentage} = \frac{4730}{215} $
$ \text{Friend's Percentage} = 22\% $
Therefore, the friend scored 22% of the maximum marks.
In an election between two candidates, a candidate who got $30\%$ of the total votes is defeated by $15000$ votes. The number of votes obtained by the winning candidate is:-
If A earns \(33\frac{1}{3}%\) more than B, then how much percent does B earn less than A?