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Question

In the RSA public key cryptosystem, the private and public keys are $(e, n)$ and $(d, n)$ respectively, where $n = p \times q$ and $p$ and $q$ are large primes. Besides, $n$ is public and $p$ and $q$ are private. Let M be an integer such that $0 <M< n$ and $\phi(n) = (p-1)(q - 1)$. now consider the following equations.
I. M’ =\( M^e\) mod n  M =\( (M')^d\) mod n 

II. ed ≡1 mod n 

III. ed ≡1 mod f(n) 

IV. M’ = \(M^e \)mod f(n) 

M = \( (M')^d\) mod
Which of the above equations correctly represent RSA cryptosystem?

The correct answer is
I and III

Understanding RSA Cryptosystem Equations

The RSA cryptosystem relies on specific mathematical relationships between keys and the encryption/decryption process. Let's analyze the given equations to determine which ones accurately represent the RSA algorithm.

RSA Encryption and Decryption Process

The core operations in RSA are encryption and decryption. Given a plaintext message $M$ (where $0 < M < n$), the ciphertext $M'$ is calculated using the public key $(e, n)$ as follows:

Equation I (Encryption Part): \( M' \equiv M^e \pmod{n} \)

To recover the original message $M$ from the ciphertext $M'$, the private key $(d, n)$ is used:

Equation I (Decryption Part): \( M \equiv (M')^d \pmod{n} \)

These two equations correctly define the fundamental encryption and decryption steps in the RSA algorithm. The modulus used for these operations is $n$. Therefore, Equation I is a correct representation.

Key Relationship: Exponents and Euler's Totient Function

For the decryption process to successfully recover the original message, the private exponent $d$ must be related to the public exponent $e$ and the number $n$. This relationship involves Euler's totient function, denoted as $\phi(n)$. It is known that $\phi(n) = (p-1)(q-1)$ for $n = p \times q$ where $p$ and $q$ are prime numbers.

The condition that ensures $M \equiv (M'^d) \equiv (M^e)^d \equiv M^{ed} \equiv M \pmod{n}$ is:

Equation III: \( ed \equiv 1 \pmod{\phi(n)} \)

This means that $d$ is the modular multiplicative inverse of $e$ modulo $\phi(n)$. This equation correctly describes the relationship required between $e$ and $d$ for RSA to work. Therefore, Equation III is also a correct representation.

Why Other Equations Are Incorrect

Let's examine why Equations II and IV are not correct representations of the standard RSA cryptosystem:

  • Equation II: \( ed \equiv 1 \pmod{n} \) This equation suggests that the relationship between $e$ and $d$ should hold modulo $n$. However, the correct condition for RSA relies on the modular inverse property related to $\phi(n)$, not $n$ itself. Using $n$ as the modulus here is incorrect.
  • Equation IV: \( M' \equiv M^e \pmod{f(n)} \) and \( M \equiv (M')^d \pmod{f(n)} \) This equation incorrectly uses $f(n)$ (which usually represents $\phi(n)$ in this context) as the modulus for the encryption and decryption operations. The actual encryption and decryption must be performed modulo $n$, the public modulus. While the relationship $ed \equiv 1 \pmod{f(n)}$ (or $\phi(n)$) is correct, applying the exponentiation modulo $f(n)$ is wrong.

Conclusion

Based on the analysis of the RSA cryptosystem's requirements:

  • Equation I correctly defines the encryption ($M' \equiv M^e \pmod{n}$) and decryption ($M \equiv (M')^d \pmod{n}$) processes.
  • Equation III correctly states the necessary relationship between the exponents ($ed \equiv 1 \pmod{\phi(n)}$).

Therefore, the equations that correctly represent the RSA cryptosystem are I and III.

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Important Questions from Cryptography - Teaching

  1. In symmetric key cryptography, if every person in a group of 12 people needs to communicate with every other person in the group, how many secret keys are required?
  2. Match the following:
    Match correctly the cryptographic algorithm with their corresponding key-length.
    1.DESa.128-256 bits
    2.Rj indealb.1-448 bits
    3.RC4c.56 bits
    4.Blowfishd.1-2048 bits
  3. Decryption of the ciphertext "Z" with the key pair (7, 2) in modulus 26 is
  4. Let M be a message consisting of 50 AES blocks. Alice encrypts using CBC mode and transmits the resulting ciphertext to Bob. Due to a network error, ciphertext block number 45 is corrupted during transmission. All other ciphertext blocks are transmitted and received correctly. Once Bob decrypts the received ciphertext, number of plaintext blocks corrupted is
  5. Match the type of attack and its prevention mechanism:
    1.Brute-Force Attacka.Change of keys
    2.Statistical Attackb.Number of possible keys are large
    3.Pattern Attackc.Hide the characteristics of the
    language
    4.Known - Plain Text Attackd.Ciphertext is as random as
    possible
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