The question asks for the total number of secret keys needed in a group of 12 people, where each person must be able to communicate securely with every other person using symmetric key cryptography.
In symmetric key cryptography, a unique shared secret key is required for every pair of individuals who need to communicate. If there are 'n' people in a group, and each person needs to communicate with every other person, we need to find the number of unique pairs that can be formed from this group.
This is a classic combination problem. We need to choose 2 people from a group of 'n' to form a pair, and each pair requires one secret key. The formula for combinations is:
$ C(n, k) = \frac{n!}{k!(n-k)!} $
In our case, we are forming pairs (k=2) from a group of 12 people (n=12). So, the formula simplifies to:
$ \text{Number of keys} = C(n, 2) = \frac{n \times (n-1)}{2} $
Therefore, 66 unique secret keys are required for every person in a group of 12 to communicate with every other person using symmetric key cryptography.
| 1. | DES | a. | 128-256 bits |
| 2. | Rj indeal | b. | 1-448 bits |
| 3. | RC4 | c. | 56 bits |
| 4. | Blowfish | d. | 1-2048 bits |
In the RSA public key cryptosystem, the private and public keys are $(e, n)$ and $(d, n)$ respectively, where $n = p \times q$ and $p$ and $q$ are large primes. Besides, $n$ is public and $p$ and $q$ are private. Let M be an integer such that $0 <M< n$ and $\phi(n) = (p-1)(q - 1)$. now consider the following equations.
I. M’ =\( M^e\) mod n M =\( (M')^d\) mod n
II. ed ≡1 mod n
III. ed ≡1 mod f(n)
IV. M’ = \(M^e \)mod f(n)
M = \( (M')^d\) mod
Which of the above equations correctly represent RSA cryptosystem?
| 1. | Brute-Force Attack | a. | Change of keys |
| 2. | Statistical Attack | b. | Number of possible keys are large |
| 3. | Pattern Attack | c. | Hide the characteristics of the language |
| 4. | Known - Plain Text Attack | d. | Ciphertext is as random as possible |