In the figure given, parallel lines, AB and CD, are intercepted by a transversal t at E and F, respectively. If EG is the angle bisector of $\angle AEF$, find $\angle EGF$.
∠AEF = Corresponding ∠CFt (external) = 70°.
∠GEF = ∠AEF ÷ 2 = 70° ÷ 2 = 35°.
∠EFG = 180° − (70° + 25°) = 85°.
∠EGF = 180° − (35° + 85°) = 180° − 120° = 60°.
Important Questions from Lines and Angles
There are three points P, Q and R on a straight line such that PQ : QR = 3 : 5. If n is the number of possible values of PQ : PR, then what is n equal to ?
Two cars start from a point at the same time and travel on two different roads at right angles to each other. Their speed is 18 km/h and 72 km/h respectively. What will be the distance between them after 6 seconds?
Express 65° in radian :
The measure of an angle for which the measure of the supplement is four times the measure of the complement is:
AB||CD and EF is the transversal meeting AB and CD at P and Q, respectively. If ∠APE = 6x and ∠PQD = 4x, then ∠APQ =______.
