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Question

In the figure given, parallel lines, AB and CD, are intercepted by a transversal t at E and F, respectively. If EG is the angle bisector of $\angle AEF$, find $\angle EGF$.

The correct answer is
$60^\circ$

∠AEF = Corresponding ∠CFt (external) = 70°.

∠GEF = ∠AEF ÷ 2 = 70° ÷ 2 = 35°.

∠EFG = 180° − (70° + 25°) = 85°.

∠EGF = 180° − (35° + 85°) = 180° − 120° = 60°.

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Important Questions from Lines and Angles

  1. If the angles of a triangle are in the ratio of 2 : 5 : 8, then find the value of the largest angle.

    A. 36°

    B. 96° 

    C. 84° 

    D. 60° 

  2. If (6y + 70)° and (3y + 47)° are supplementary angles, find the value of y.

    A. 12

    B. 15

    C. 7

    D. 10

  3. An angle is 60° more than one-fifth of its complement. Find the smaller angle in degrees.

    A. 65°

    B. 35°

    C. 25°

    D. 45°

  4. If the angles of a triangle are in the ratio of 2 : 3 : 5, then find the ratio of the greatest angle to the smallest angle.

    A. 7 : 2

    B. 5 : 2

    C. 5 : 3

    D. 3 : 5

  5. A straight angle is equal to?

    A. 90°

    B. 180°

    C. 270°

    D. 360°

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