All Exams Test series for 1 year @ ₹349 only
Question

In the electronic spectrum of $[CrF_6]^{3-}$, absorption bands observed at $670$, $440$, and $290$ nm are, respectively, due to the transitions

The correct answer is
$^4A_{2g}\rightarrow^4T_{2g}$, $^4A_{2g}\rightarrow^4T_{1g}(F)$ and $^4A_{2g}\rightarrow^4T_{1g}(P)$

$[CrF_6]^{3-}$ Electronic Spectrum Analysis

The complex $[CrF_6]^{3-}$ contains chromium in the $+3$ oxidation state ($Cr^{3+}$), which has a $d^3$ electron configuration. In an octahedral crystal field, the ground state term symbol for a $d^3$ ion is $^4A_{2g}$.

d-d Transitions in Octahedral Complexes

The absorption bands observed in the electronic spectrum of transition metal complexes arise from d-d electronic transitions. For a $d^3$ octahedral complex, the allowed spin transitions from the ground state $^4A_{2g}$ typically occur to the following excited states, listed in increasing order of energy:

  • $^4T_{2g}$
  • $^4T_{1g}(F)$
  • $^4T_{1g}(P)$

Wavelength and Energy Relationship

The energy ($E$) of absorbed photons is inversely proportional to the wavelength ($\lambda$) according to the equation $E = \frac{hc}{\lambda}$, where $h$ is Planck's constant and $c$ is the speed of light. Therefore:

  • Longer wavelengths correspond to lower energy transitions.
  • Shorter wavelengths correspond to higher energy transitions.

Matching Transitions to Absorption Bands

The absorption bands are given at $670$ nm, $440$ nm, and $290$ nm. We match these wavelengths to the energy order of the transitions:

  1. Lowest Energy (Longest Wavelength): $670$ nm corresponds to the transition with the smallest energy gap, which is $^4A_{2g}\rightarrow^4T_{2g}$.
  2. Intermediate Energy: $440$ nm corresponds to the transition with the next higher energy gap, which is $^4A_{2g}\rightarrow^4T_{1g}(F)$.
  3. Highest Energy (Shortest Wavelength): $290$ nm corresponds to the transition with the largest energy gap, which is $^4A_{2g}\rightarrow^4T_{1g}(P)$.

Conclusion

Therefore, the absorption bands observed at $670$, $440$, and $290$ nm are, respectively, due to the transitions $^4A_{2g}\rightarrow^4T_{2g}$, $^4A_{2g}\rightarrow^4T_{1g}(F)$, and $^4A_{2g}\rightarrow^4T_{1g}(P)$.

Was this answer helpful?

Important Questions from Electronic Spectra

  1. The UV-visible spectrum of $[Ni(en)_3]^{2+}$ (en = ethylenediamine) shows absorbance maxima at $11200 \text{ cm}^{-1}$, $18350 \text{ cm}^{-1}$, and $29000 \text{ cm}^{-1}$.
    Absorbance maximumElectronic transition
    (a) $11200 \text{ cm}^{-1}$(i) $^3A_{2g} \to ^3T_{1g} (F)$
    (b) $18350 \text{ cm}^{-1}$(ii) $^3A_{2g}\to^3T_{2g}$
    (c) $29000 \text{ cm}^{-1}$(iii) $^3A_{2g}\to^3T_{1g} (P)$

    [Given: Atomic number of Ni = 28]
    The correct match(es) between absorbance maximum and electronic transition is/are
  2. In aqueous solution of $K_4[Fe(CN)_6]$, the allowed transition(s) is (are)
  3. The $VO_4^{3-}$, $CrO_4^{2-}$ and $MnO_4^-$ ions exhibit intense ligand to metal charge transfer transition. The wavelengths of this transition follow the order
  4. The lowest energy d $\rightarrow$ d transition of the complexes follow the order
  5. The intense red color of $[Fe(bpy)_3]^{2+}$ (bpy = 2,2'-bipyridine) is due to
Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App