In the balanced reaction $2Al + 3Cl_2 \rightarrow 2AlCl_3$, what is the mole ratio of aluminium toaluminium chloride?
This question asks us to find the mole ratio between aluminium (Al) and aluminium chloride (AlCl3) in a given balanced reaction.
Understanding Mole Ratios in Balanced Reactions
A mole ratio represents the relative number of moles of reactants and products involved in a balanced chemical reaction. These ratios are determined by the stoichiometric coefficients (the numbers in front of the chemical formulas) in the balanced equation.
Analyzing the Balanced Reaction
The provided balanced reaction is:
$$2Al + 3Cl_2 \rightarrow 2AlCl_3$$
In this equation:
- The coefficient for Aluminium (Al) is 2. This means 2 moles of Al are consumed.
- The coefficient for Aluminium Chloride (AlCl3) is 2. This means 2 moles of AlCl3 are produced.
Calculating the Mole Ratio
The mole ratio of aluminium to aluminium chloride is directly derived from their coefficients in the balanced reaction.
Mole ratio of Al : AlCl3 = (Coefficient of Al) : (Coefficient of AlCl3)
Mole ratio of Al : AlCl3 = $2 : 2$
Therefore, for every 2 moles of Aluminium consumed, 2 moles of Aluminium Chloride are produced.
Comparing with Options
The calculated mole ratio of aluminium to aluminium chloride is 2:2. This matches one of the provided options.
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