In randomly constituted two groups-experimental and control, a researcher obtains the following results after using a parametric 't' test: Value of t = 3 for N = 300 On the basis of this evidence which decision in respect of substantive research hypothesis and the null hypothesis will be justified?
Rejecting the null hypothesis and accepting the research hypothesis
In research, we often compare groups or test interventions. A common statistical tool for comparing the means of two groups is the parametric t-test. The goal is to determine if any observed difference between the groups is statistically significant or likely due to random chance.
This question involves interpreting the results of a t-test conducted on two randomly constituted groups: an experimental group and a control group. The researcher obtained a t-value of $\text{t} = 3$ with a total sample size of $\text{N} = 300$. We need to decide on the substantive research hypothesis and the null hypothesis based on this result.
In statistical testing, we work with two main hypotheses:
The t-test calculates a t-value, which measures the difference between the group means relative to the variability within the groups. A larger absolute t-value suggests a greater difference between the group means.
To make a decision, the calculated t-value is compared to a critical t-value from a t-distribution table or using statistical software. The critical value depends on the chosen significance level (alpha, usually 0.05) and the degrees of freedom (df). For a two-sample t-test, degrees of freedom are typically $\text{N}_1 + \text{N}_2 - 2$, which for a total sample of $\text{N}=300$ (assuming roughly equal groups) would be close to $300 - 2 = 298$.
The decision rule is:
With a large sample size like $\text{N} = 300$ (and df $\approx 298$), the t-distribution is very close to the standard normal distribution (Z-distribution). The critical Z-values are approximately 1.96 for a 0.05 significance level (two-tailed) and 2.58 for a 0.01 significance level (two-tailed).
The obtained t-value is 3. Since $|3| > 1.96$ and even $|3| > 2.58$, the result $\text{t} = 3$ is highly statistically significant at both the 0.05 and 0.01 levels. This means the observed difference between the experimental and control groups is very unlikely to have occurred by random chance if the null hypothesis were true.
Since the t-test result ($\text{t} = 3$) is statistically significant, we make the following decisions:
Let's look at the given options based on our decision:
Based on the statistically significant t-test result ($\text{t}=3$, $\text{N}=300$), the null hypothesis must be rejected, and the substantive research hypothesis must be accepted. This indicates that there is likely a real difference between the experimental and control groups.
| t-Test Result | Statistical Significance | Decision on Null Hypothesis ($\text{H}_0$) | Decision on Research Hypothesis ($\text{H}_1$) |
|---|---|---|---|
| Calculated $|\text{t}|$ > Critical t | Statistically Significant | Reject $\text{H}_0$ | Accept $\text{H}_1$ |
| Calculated $|\text{t}|$ $\le$ Critical t | Not Statistically Significant | Fail to Reject $\text{H}_0$ | Reject $\text{H}_1$ |
| Hypothesis | What it states | Decision when t-test is Significant | Decision when t-test is Not Significant |
|---|---|---|---|
| Null Hypothesis ($\text{H}_0$) | No difference/effect | Reject $\text{H}_0$ | Fail to Reject $\text{H}_0$ (or Accept $\text{H}_0$) |
| Research Hypothesis ($\text{H}_1$) | Significant difference/effect | Accept $\text{H}_1$ (or Support $\text{H}_1$) | Reject $\text{H}_1$ |
Given below are two statements
Statement I: The qualitative data are powerful because they are collected from very sensitive social, historical and temporal context.
Statement II: Context sensitivity cannot be completely removed from the qualitative data.
In light of the above statements, choose the correct answer from the options given below
Given below is a summary of ANOVA for four groups of students tested in a research project:
| Source of variance | SS (Sum of squares) | df (Degree of freedom) | MS (Mean sum of squares) |
| Between groups | 76 | 3 | 23.33 |
| Within groups | 122 | 16 | 7.62 |
What will be the value of 'F' for the above data?
An investigator used ANOVA to compare four groups of students on numerical ability on the basis of a test. After analysis of raw scores, the following results were obtained:
| Source of variation | df | Sum of Squares |
| Between Groups | 3 | 625.00 |
| Within Groups | 36 | 2128.00 |
The value of F-ratio would be approximate:
Given below are two statements, one labelled as Assertion (A) and the other labelled as Reason (R). Read the statements and choose the correct answer using the code given below.
Assertion (A): Homogenous tests have low reliability.
Reason (R): The range of test scores affects reliability.
An investigator commits Type I error in testing hypothesis when he / she