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Question

In optical microscopy, which one of the following combinations of wavelength ($\lambda$) and numerical aperture (NA) provides the best spatial resolution?

The correct answer is
$\lambda = 400$ nm and NA = 1.2

Optical Microscopy Resolution Factors

The spatial resolution in optical microscopy, which is the smallest distance between two points that can be distinguished as separate, is primarily determined by the wavelength of light used and the numerical aperture (NA) of the objective lens.

The relationship is described by the Abbe diffraction limit formula:

$ d = \frac{\lambda}{2 \times NA} $

Where:

  • $d$ is the minimum resolvable distance (resolution)
  • $\lambda$ is the wavelength of the illuminating light
  • $NA$ is the numerical aperture of the objective lens

To achieve the best spatial resolution (i.e., the smallest possible value for $d$), we need to:

  • Minimize the wavelength ($\lambda$).
  • Maximize the numerical aperture ($NA$).

Resolution Analysis of Options

Let's analyze the options based on these principles:

  • Option 1: $\lambda = 400$ nm, NA = 1.0. Resolution is proportional to $400 / 1.0 = 400$.
  • Option 2: $\lambda = 600$ nm, NA = 1.2. Resolution is proportional to $600 / 1.2 = 500$.
  • Option 3: $\lambda = 400$ nm, NA = 1.2. Resolution is proportional to $400 / 1.2 \approx 333.3$.
  • Option 4: $\lambda = 600$ nm, NA = 1.0. Resolution is proportional to $600 / 1.0 = 600$.

Comparing the proportional values ($400$, $500$, $333.3$, $600$), the smallest value ($\approx 333.3$) corresponds to the best spatial resolution.

Conclusion

The combination providing the best spatial resolution is the one with the shortest wavelength and the highest numerical aperture.

Therefore, $\lambda = 400$ nm and NA = 1.2 offers the superior resolution.

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