In Mathematics paper, the number of students' obtained marks are distributed in the given figure and total marks of this paper is 200. What is percentage (round off) of student who are 1st division if 60% mark are set for first division ?
To find the percentage of students who are in the 1st division, we first determine the marks required for the 1st division. The total marks for the paper are 200, and 60% marks are needed for the 1st division.
Calculate the 1st division cutoff:
\(60\% \text{ of } 200 = \frac{60}{100} \times 200 = 120\)
The marks required for 1st division is 120 or above. Now, we look at the distribution of students' marks:
From the data given:
- Number of students scoring between 120-140 marks: 75
- Number of students scoring between 140-160 marks: 55
- Number of students scoring between 160-180 marks: 40
- Number of students scoring between 180-200 marks: 15
Total students in 1st division = \(75 + 55 + 40 + 15 = 185\)
Total number of students = \(10 + 18 + 32 + 45 + 60 + 75 + 55 + 40 + 15 = 350\)
Percentage of 1st division students = \(\frac{185}{350} \times 100 \approx 52.86\%\)
After rounding off, the percentage is 53%.
Therefore, the correct answer is 53%.
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