In a Vernier calliper, 39 main scale divisions are divided into 40 equal points on the Vernier scale. Then what is its least count (LC) in mm? (Take the value of main scale division = 1mm).
0.025
This question asks for the calculation of the least count (LC) of a Vernier caliper based on specific information about its main scale divisions (MSD) and Vernier scale divisions (VSD).
A Vernier caliper is a precision measuring instrument used to measure linear dimensions accurately. It consists of two scales:
The precision of a Vernier caliper is determined by its least count, which is the smallest measurement that can be accurately measured using the instrument.
The least count (LC) of a Vernier caliper can be calculated using the following relationship:
Formula 1: LC = 1 MSD - 1 VSD
Where:
1 MSD is the value of one Main Scale Division.1 VSD is the value of one Vernier Scale Division.Alternatively, a more direct formula can be used when the specific condition mentioned in the problem is met:
Formula 2: LC = Value of 1 MSD / Total Number of Divisions on Vernier Scale
From the question, we are given:
1 MSD) = 1 mmThis means that 40 Vernier Scale Divisions (40 VSD) are equal to 39 Main Scale Divisions (39 MSD).
1 MSD = 1 mmTotal VSD = 40LC = Value of 1 MSD / Total Number of Divisions on Vernier ScaleLC = 1 mm / 40LC = 0.025 mm40 VSD = 39 MSD.1 VSD = (39 / 40) * 1 MSD1 VSD = (39 / 40) * 1 mm = 0.975 mmLC = 1 MSD - 1 VSDLC = 1 mm - 0.975 mmLC = 0.025 mmBoth methods yield the same result.
The least count of the Vernier caliper described in the question is 0.025 mm.
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