In a single-phase transformer, the ratio of transformation is 2 and the secondary resistance is 0.24 Ω. Find the resistance of secondary in terms of primary.
0.06 Ω
In the study of electrical machines, a single-phase transformer is a crucial device used to step up or step down AC voltages. When analyzing the performance of a transformer, it is often necessary to refer the impedance (or resistance) from one side of the transformer to the other. This process simplifies the equivalent circuit of the transformer, making calculations easier. The core concept behind this referral is the transformation ratio of the transformer.
The transformation ratio (often denoted by \(k\) or \(a\)) of a transformer is defined as the ratio of the secondary winding voltage to the primary winding voltage, or the ratio of secondary turns to primary turns.
\[R_2' = \frac{R_2}{k^2}\]
\[R_2' = R_2 \times a^2\]
In this problem, the "ratio of transformation" is given as 2. In most contexts, especially when not specified otherwise, this typically refers to \(k = \frac{N_2}{N_1}\). We will proceed with this common interpretation to calculate the resistance of secondary in terms of primary.
To determine the resistance of secondary in terms of primary, we apply the appropriate formula for referring secondary resistance to the primary side.
Given information:
Formula used:
\[R_2' = \frac{R_2}{k^2}\]
Step-by-step calculation:
\[R_2' = \frac{0.24 \, \Omega}{(2)^2}\]
\[k^2 = 2^2 = 4\]
\[R_2' = \frac{0.24 \, \Omega}{4}\]
\[R_2' = 0.06 \, \Omega\]
Thus, the resistance of secondary in terms of primary is 0.06 \(\Omega\). This process of impedance transformation is fundamental for analyzing the equivalent circuit of a single-phase transformer.
Let's compare the calculated value of the secondary resistance referred to the primary side with the given options.
| Option | Value (\(\Omega\)) |
|---|---|
| 1 | 0.6 |
| 2 | 0.48 |
| 3 | 0.12 |
| 4 | 0.06 |
Our calculated value of 0.06 \(\Omega\) perfectly matches Option 4, confirming the correct application of the transformation ratio formula for referring secondary resistance to the primary side in a single-phase transformer.
What is the condition at which a transformer gives maximum efficiency?
For a single phase transformer, the maximum efficiency occurs at 75% of the load, then \(\rm \frac{iron \ loss \ at\ full \ load }{copper \ loss \ at\ full \ load}=?\)
A single-phase \(400\;V,\;50\;Hz\) transformer has an iron loss of \(5000\;W\) at the rated condition. When operated at \(200\;V,\;25\;Hz\), the iron loss is \(2000\;W\). When operated at \(416\;V,\;52\;Hz\), the value of the hysteresis loss divided by the eddy current loss is ______.
The full load copper loss and iron loss of a transformer are 6400 W and 5000 W respectively the copper loss and iron loss at half load will be respectively.