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Question

In a race, an athlete covers a distance of 402 m in 134 sec in the first lap. He covers the second lap of the same length in 67 sec. What is the average speed (in m/sec) of the athlete?

The correct answer is

4

The problem requires calculating the average speed of an athlete over two laps around a track, each 402 meters long. To find the average speed, we first calculate the total distance covered and the total time taken.

Step 1: Calculate Total Distance
The athlete covers 402 meters in each lap. For two laps, the total distance is:

\[ \text{Total Distance} = 402 \, \text{m} + 402 \, \text{m} = 804 \, \text{m} \]

Step 2: Calculate Total Time
The first lap takes 134 seconds, and the second lap takes 67 seconds. Therefore, the total time is:

\[ \text{Total Time} = 134 \, \text{sec} + 67 \, \text{sec} = 201 \, \text{sec} \]

Step 3: Calculate Average Speed
The average speed is the total distance divided by the total time. Use the formula:

\[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{804 \, \text{m}}{201 \, \text{sec}} \]

Calculating this gives:

\[ \text{Average Speed} = 4 \, \text{m/sec} \]

The average speed of the athlete is therefore 4 meters per second.

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Important Questions from Average Speed

  1. A car runs first 275 km at an average speed of 50 km/h and the next 315 km at an average speed of 70 km/h. What is the average speed ( in km/h) for the entire journey?

  2. Akhil rides first 12 km at a speed of 16 km/h and further 6 km at a speed of 20 km/h. Find his average speed (in km/h).

  3. Shyam drives his car 30 km at a speed of 45 km/h and, for the next 1 h 20 m, he drives it at a speed of 51 km/h. Find his average speed (in km/h) for the entire journey.

  4. X and Y travel a distance of 90 km each such that the speed of Y is greater than that of X. The sum of their speeds is 100 km/h and the total time taken by both is 3 hours 45 minutes. The ratio of the speed of X to that of Y is:

  5. If a man travels at \(\frac{1}{x}\) km/h on a journey and returns at  \(\rm \frac{1}{x^2}\) km/h, then his average speed for the journey is:

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