In a half-subtractor circuit with X and Y as inputs, the Borrow (M) and Difference (N = X - Y) are given by
M = X̅Y, N = X ⊕ Y
A half-subtractor is a combinational logic circuit that performs subtraction of two single-bit binary numbers. It takes two inputs, usually denoted as X (minuend) and Y (subtrahend), and produces two outputs: Difference (N) and Borrow (M).
The operation of a half-subtractor can be understood by looking at its truth table, which shows the outputs for all possible combinations of inputs.
Let's construct the truth table for a half-subtractor with inputs X and Y, and outputs Difference (N) and Borrow (M).
| X (Minuend) | Y (Subtrahend) | N (Difference = X - Y) | M (Borrow) |
|---|---|---|---|
| 0 | 0 | 0 (0 - 0 = 0) | 0 |
| 0 | 1 | 1 (0 - 1 = 1, with a borrow) | 1 |
| 1 | 0 | 1 (1 - 0 = 1) | 0 |
| 1 | 1 | 0 (1 - 1 = 0) | 0 |
From the truth table, we can observe the pattern for the Difference output (N). The output N is '1' when the inputs X and Y are different (i.e., one is '0' and the other is '1'). This behavior is exactly what an Exclusive OR (XOR) gate performs.
Therefore, the Boolean expression for the Difference (N) is:
\(N = X \oplus Y\)
Now, let's analyze the Borrow output (M) from the truth table. The Borrow (M) output is '1' only in one specific case:
This means that a borrow is generated only when we try to subtract a '1' from a '0'. In Boolean algebra, this condition can be represented by the logical AND operation of X-bar (NOT X) and Y.
Therefore, the Boolean expression for the Borrow (M) is:
\(M = \overline{X}Y\)
Combining the derived expressions, for a half-subtractor circuit with X and Y as inputs:
These expressions accurately describe the functionality of a half-subtractor. When comparing these with the provided options, we find that the option stating \(M = \overline{X}Y\) and \(N = X \oplus Y\) aligns perfectly with our derivations.
A full adder and an XOR gate are used to design a digital circuit with inputs X, Y, and Z, and output F, as shown below. The input Z is connected to the carry-in input of the full adder. If the input Z is set to logic ‘1', then the circuit functions as __________ with X and Y as inputs.
