In a group of people, 70% are men and 30% are women. The average age of the men is 50 years and that of the women is 40 years. Find the average age of all the members in the group (in years).
47
This problem involves finding the average age of an entire group when we know the proportions and average ages of its subgroups (men and women). This requires using the concept of a weighted average.
A weighted average is used when different data points contribute differently to the final average. In this case, the contribution of the men's average age and the women's average age to the overall group average is weighted by their respective proportions in the group.
The formula for a weighted average is:
\(\text{Weighted Average} = \frac{\sum (\text{Weight} \times \text{Value})}{\sum \text{Weight}}\)
In this problem:
We are given the following information:
We need to find the average age of all the members in the group.
Let \(P_m\) be the percentage of men and \(A_m\) be the average age of men.
Let \(P_w\) be the percentage of women and \(A_w\) be the average age of women.
The total percentage of the group is \(P_m + P_w = 70\% + 30\% = 100\%\).
Using the weighted average formula, the average age of the group (\(A_{group}\)) is:
\(A_{group} = \frac{(P_m \times A_m) + (P_w \times A_w)}{P_m + P_w}\)
Since the percentages are out of 100, we can use the percentage values directly in the numerator and divide by the total percentage (100), or use decimal equivalents (0.70 and 0.30) and divide by 1 (0.70 + 0.30).
Using percentages:
\(A_{group} = \frac{(70 \times 50) + (30 \times 40)}{70 + 30}\)
\(A_{group} = \frac{(70 \times 50) + (30 \times 40)}{100}\)
Now, perform the multiplications:
\(70 \times 50 = 3500\)
\(30 \times 40 = 1200\)
Substitute these values back into the formula:
\(A_{group} = \frac{3500 + 1200}{100}\)
\(A_{group} = \frac{4700}{100}\)
\(A_{group} = 47\)
So, the average age of all the members in the group is 47 years.
Alternatively, using decimal proportions:
\(P_m = 0.70\)
\(P_w = 0.30\)
\(A_{group} = \frac{(0.70 \times 50) + (0.30 \times 40)}{0.70 + 0.30}\)
\(A_{group} = \frac{35 + 12}{1.00}\)
\(A_{group} = \frac{47}{1}\)
\(A_{group} = 47\)
The result is the same: 47 years.
The average age of all the members in the group is 47 years.
| Subgroup | Percentage | Average Age | Weighted Contribution |
|---|---|---|---|
| Men | 70% (or 0.70) | 50 years | \(70 \times 50 = 3500\) (or \(0.70 \times 50 = 35\)) |
| Women | 30% (or 0.30) | 40 years | \(30 \times 40 = 1200\) (or \(0.30 \times 40 = 12\)) |
| Total Group | 100% (or 1.00) | Average Age = ? | Sum = \(3500 + 1200 = 4700\) (or \(35 + 12 = 47\)) |
Average Age = \(\frac{\text{Sum of Weighted Contributions}}{\text{Total Percentage or Proportion}}\) = \(\frac{4700}{100}\) or \(\frac{47}{1}\) = 47 years.
| Concept | Explanation | Formula Used |
|---|---|---|
| Average Age | Sum of ages divided by the number of people. | \( \text{Average} = \frac{\text{Sum of Ages}}{\text{Number of People}} \) |
| Weighted Average | Average considering the relative importance (weights) of different values. | \( \text{Weighted Avg} = \frac{\sum (\text{Weight} \times \text{Value})}{\sum \text{Weight}} \) |
| This Problem | Finding the overall average age of a group from subgroup averages and proportions. | \( A_{group} = \frac{(P_m \times A_m) + (P_w \times A_w)}{P_m + P_w} \) |
Weighted averages are commonly used in various fields, not just for calculating average age. Here are a few examples:
Understanding weighted averages helps in accurately representing the central tendency of data points when their contributions are not equal.
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