Understanding the Coding Decoding Pattern

In coding-decoding questions like this, we need to identify the specific rule or pattern used to transform the letters of the original word into the letters of the coded word. Let's look at the examples provided:

• 'PRISON' is coded as 'QTJUPP'
• 'RECORD' is coded as 'SGDQSF'

We will analyze the relationship between the letters in the original words and their corresponding letters in the coded words.

Analyzing the Pattern in PRISON → QTJUPP

Let's compare each letter of 'PRISON' with the corresponding letter in 'QTJUPP':

• P → Q (Moving 1 step forward in the alphabet: P + 1 = Q)
• R → T (Moving 2 steps forward in the alphabet: R + 2 = T)
• I → J (Moving 1 step forward in the alphabet: I + 1 = J)
• S → U (Moving 2 steps forward in the alphabet: S + 2 = U)
• O → P (Moving 1 step forward in the alphabet: O + 1 = P)
• N → P (Moving 2 steps forward in the alphabet: N + 2 = P)

The pattern observed here is adding 1 to the 1st, 3rd, and 5th letters and adding 2 to the 2nd, 4th, and 6th letters.

Analyzing the Pattern in RECORD → SGDQSF

Let's verify if the same pattern applies to the second example:

• R → S (R + 1 = S)
• E → G (E + 2 = G)
• C → D (C + 1 = D)
• O → Q (O + 2 = Q)
• R → S (R + 1 = S)
• D → F (D + 2 = F)

Yes, the pattern is consistent: +1, +2, +1, +2, +1, +2.

Applying the Pattern to OBTAIN

Now, we will apply the same coding pattern (+1, +2, +1, +2, +1, +2) to the word 'OBTAIN' to find its coded form.

• O (1st letter): O + 1 = P
• B (2nd letter): B + 2 = D
• T (3rd letter): T + 1 = U
• A (4th letter): A + 2 = C
• I (5th letter): I + 1 = J
• N (6th letter): N + 2 = P

Combining these coded letters, we get PDUCJP.

Thus, 'OBTAIN' is written as 'PDUCJP' in that code language.

Final Coded Word

Based on the identified pattern, the coded word for 'OBTAIN' is PDUCJP.