To solve the problem given, let's first understand the statement:
If \(x\%\) of \(a\) is equal to \(y\%\) of \(b\), then mathematically it can be represented as:
\(\frac{x}{100} \times a = \frac{y}{100} \times b\)
By simplifying, we can find the relation between \(a\) and \(b\) as:
\(\Rightarrow x \times a = y \times b\)
\(\Rightarrow a = \frac{y}{x} \times b\)
Now, we need to find what percent of \(a\) is \(z\%\) of \(b\).
Let's express \(z\%\) of \(b\):
\(\frac{z}{100} \times b\)
We now need to find what percent this quantity is of \(a\).
Using the relation between \(a\) and \(b\) from above:
\(\Rightarrow a = \frac{y}{x} \times b\)
Thus, the percentage of \(a\) is given by
\(\frac{\left(\frac{z}{100} \times b\right)}{\left(\frac{y}{x} \times b\right)} \times 100 = \frac{zx}{y}\)
Therefore, the correct answer is \(\frac{zx}{y}\).
A number p increased by p% of 99 equals 99 increased by 99% of p. What is (p + 51)% of 928 + 72?
Amina saves 16% of her income. Now her income is increased by 20% but she still saves the same amount as before. What is the percentage increase in her expenditure?
What is 12% of 4% of 7% of 2 × 10 6 ?
Vignesh spends 42% of his monthly salary on food, 16% on house rent, 11% on entertainment and 7% on conveyance. But due to some family function, he has to borrow Rs. 12,000 from a money leader to meet the expenses of Rs. 18,000 What is his monthly salary?
If X is 12.25% more than Y. then Y is approximately_____ less than X.