We are given the equations:
To find the relation, we first square both equations:
Next, we add the squared equations together:
$x^2 + y^2 = a^2\sin^2\theta + a^2\cos^2\theta$
Factor out $a^2$ from the right side:
$x^2 + y^2 = a^2(\sin^2\theta + \cos^2\theta)$
Using the fundamental trigonometric identity $\sin^2\theta + \cos^2\theta = 1$, we substitute this into the equation:
$x^2 + y^2 = a^2(1)$
This simplifies to the final relation:
$x^2 + y^2 = a^2$
What is cos 2β equal to ?
What is the value of sec2γ?
On simplifying \(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}} + \frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}}\) we get
(1 – sin A + cos A) 2is equal to
What is \(\frac{{\cos {\rm{\theta }}}}{{1 - \tan {\rm{\theta }}}} + \frac{{\sin {\rm{\theta }}}}{{1 - \cot {\rm{\theta }}}}\) equal to?