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Question

If $x = a\sin\theta$ and $y = a\cos\theta$, then find the relation between x, y and a.

The correct answer is
$x^2 + y^2 = a^2$

Finding Relation between x, y and a

We are given the equations:

  • $x = a\sin\theta$
  • $y = a\cos\theta$

To find the relation, we first square both equations:

  • $x^2 = (a\sin\theta)^2 \implies x^2 = a^2\sin^2\theta$
  • $y^2 = (a\cos\theta)^2 \implies y^2 = a^2\cos^2\theta$

Next, we add the squared equations together:

$x^2 + y^2 = a^2\sin^2\theta + a^2\cos^2\theta$

Factor out $a^2$ from the right side:

$x^2 + y^2 = a^2(\sin^2\theta + \cos^2\theta)$

Using the fundamental trigonometric identity $\sin^2\theta + \cos^2\theta = 1$, we substitute this into the equation:

$x^2 + y^2 = a^2(1)$

This simplifies to the final relation:

$x^2 + y^2 = a^2$

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Important Questions from Trigonometric Identities

  1. What is cos 2β equal to ?

  2. What is the value of sec2γ?

  3. On simplifying \(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}} + \frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}}\) we get

  4. (1 – sin A + cos A) 2is equal to

  5. What is \(\frac{{\cos {\rm{\theta }}}}{{1 - \tan {\rm{\theta }}}} + \frac{{\sin {\rm{\theta }}}}{{1 - \cot {\rm{\theta }}}}\) equal to?

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