Question
If the volume of a cuboid is \(3x^2 - 27\), then its possible dimensions are:
The correct answer is
\(3, x - 3, x + 3\)
The expression \(3x^2 - 27\) can be factored as \(3(x^2 - 9)\), further factoring as \(3(x - 3)(x + 3)\). Thus, possible dimensions are \(3, (x - 3), (x + 3)\).
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Important Questions from Trigonometric Identities
If cos 2θ = sin θ and θ lies between 0 and 90°, then θ will be:
\(\frac{3 - 4\sin^2 \theta}{\cos^2 \theta} + 2\tan^2 \theta\) can be simplified as:
Simplify \( \left(\frac{1}{\sin^2 A} - 1\right) \), where \( 0 < A \leq 90^\circ \).
If \( \tan \theta = \frac{8}{15} \), then the value of \( \sqrt{\frac{1 - \sin \theta}{1 + \sin \theta}} \) is:
Find the value of $\cos 10^\circ \times \cos 30^\circ \times \cos 50^\circ \times \cos 70^\circ$
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