Find the value of $\cos 10^\circ \times \cos 30^\circ \times \cos 50^\circ \times \cos 70^\circ$
$\frac{3}{16}$
To find the value of the expression $\cos 10^\circ \times \cos 30^\circ \times \cos 50^\circ \times \cos 70^\circ$, we can use known trigonometric values and identities. This problem involves evaluating a product of cosine functions.
Let the given expression be represented by $P$.
$ P = \cos 10^\circ \times \cos 30^\circ \times \cos 50^\circ \times \cos 70^\circ $
We know the specific value for $\cos 30^\circ$. Substituting this known value simplifies the expression:
$ \cos 30^\circ = \frac{\sqrt{3}}{2} $
Replacing $\cos 30^\circ$ in the expression for $P$, we get:
$ P = \frac{\sqrt{3}}{2} \times (\cos 10^\circ \times \cos 50^\circ \times \cos 70^\circ) $
To evaluate the remaining product, $\cos 10^\circ \times \cos 50^\circ \times \cos 70^\circ$, we can rearrange the terms and apply a useful trigonometric identity. Notice that $50^\circ$ can be written as $60^\circ - 10^\circ$ and $70^\circ$ can be written as $60^\circ + 10^\circ$.
The product $\cos 10^\circ \times \cos 50^\circ \times \cos 70^\circ$ can be rewritten as:
$ \cos 10^\circ \times \cos(60^\circ - 10^\circ) \times \cos(60^\circ + 10^\circ) $
This matches the form of the following trigonometric identity:
$ \cos \theta \times \cos(60^\circ - \theta) \times \cos(60^\circ + \theta) = \frac{1}{4} \cos(3\theta) $
By setting $\theta = 10^\circ$, we can apply this identity directly to our expression:
$ \cos 10^\circ \times \cos 50^\circ \times \cos 70^\circ = \frac{1}{4} \cos(3 \times 10^\circ) $
Calculating the argument of the cosine:
$ = \frac{1}{4} \cos(30^\circ) $
Using the known value $\cos 30^\circ = \frac{\sqrt{3}}{2}$, we get:
$ = \frac{1}{4} \times \frac{\sqrt{3}}{2} $
$ = \frac{\sqrt{3}}{8} $
Now, we substitute the calculated value of $\cos 10^\circ \times \cos 50^\circ \times \cos 70^\circ$ back into our expression for $P$:
$ P = \frac{\sqrt{3}}{2} \times \left( \frac{\sqrt{3}}{8} \right) $
Performing the multiplication of the two fractions:
$ P = \frac{\sqrt{3} \times \sqrt{3}}{2 \times 8} $
Simplifying the numerator and the denominator:
$ P = \frac{3}{16} $
Therefore, the value of the given trigonometric expression $\cos 10^\circ \times \cos 30^\circ \times \cos 50^\circ \times \cos 70^\circ$ is $\frac{3}{16}$.
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