The following table shows the number of employees working in four different colleges A - D, along with number of males, females. teaching males, teaching females, non teaching males and non-teaching females among them in a given year. Some values are missing in the table (marked as '-') that you are expected to calculate if required. Based on the data in the table answer the questions that follow. College-wise details of employees College Number of employees Male Employees Female Employees Teaching Males Non-Teaching Males Teaching Females Non-Teaching A 756 526 - 325 - - - B - - - 215 - 254 - C - 159 - - - - - D 224 142 82 - - - -
If the number of females in college C is 147 more than the number of females in College A and the sum of teaching males and teaching females in College C is 115, then the sum of non-teaching males and non-teaching females in college C is
421
The question provides a table showing employee data for four colleges (A, B, C, D) with some missing values. We need to find the sum of non-teaching males and non-teaching females in College C, using the given additional conditions.
Here is the provided table data:
| College | Number of Employees | Male Employees | Female Employees | Teaching Males | Non-Teaching Males | Teaching Females | Non-Teaching Females |
|---|---|---|---|---|---|---|---|
| A | 756 | 526 | - | 325 | - | - | - |
| B | - | - | 215 | - | 254 | - | - |
| C | - | 159 | - | - | - | - | - |
| D | 224 | 142 | 82 | - | - | - | - |
We are specifically interested in College C. The question gives us two pieces of information about College C:
We need to find the sum of non-teaching males and non-teaching females in College C.
Step 1: Find the number of females in College A.
From the table, for College A:
Total Employees = Male Employees + Female Employees
So, Female Employees in College A = Total Employees in A - Male Employees in A
\(\text{Female Employees in A} = 756 - 526 = 230\)
There are 230 females in College A.
Step 2: Find the number of females in College C.
According to the first condition, the number of females in College C is 147 more than the number of females in College A.
\(\text{Female Employees in C} = \text{Female Employees in A} + 147\)
\(\text{Female Employees in C} = 230 + 147 = 377\)
There are 377 females in College C.
Step 3: Find the total number of employees in College C.
From the table, for College C:
We just calculated Female Employees in College C = 377.
Total Employees in College C = Male Employees in C + Female Employees in C
\(\text{Total Employees in C} = 159 + 377 = 536\)
There are 536 employees in College C.
Step 4: Find the sum of non-teaching males and non-teaching females in College C.
The total number of employees in a college is the sum of teaching staff and non-teaching staff.
Total Employees = (Teaching Males + Teaching Females) + (Non-Teaching Males + Non-Teaching Females)
We want to find (Non-Teaching Males + Non-Teaching Females) in College C.
From the second condition, we know that (Teaching Males + Teaching Females) in College C = 115.
We calculated Total Employees in College C = 536.
So, \(536 = 115 + (\text{Non-Teaching Males in C} + \text{Non-Teaching Females in C})\)
Sum of Non-Teaching staff in C = Total Employees in C - Sum of Teaching staff in C
\(\text{Non-Teaching Males in C} + \text{Non-Teaching Females in C} = 536 - 115\)
\(\text{Non-Teaching Males in C} + \text{Non-Teaching Females in C} = 421\)
The sum of non-teaching males and non-teaching females in College C is 421.
| Item | Calculation/Given | Value |
|---|---|---|
| Females in College A | 756 (Total A) - 526 (Males A) | 230 |
| Females in College C | Females in A + 147 | 230 + 147 = 377 |
| Males in College C | From table | 159 |
| Total Employees in College C | Males C + Females C | 159 + 377 = 536 |
| Teaching Males + Teaching Females in C | Given | 115 |
| Non-Teaching Males + Non-Teaching Females in C | Total C - (Teaching Males + Teaching Females) in C | 536 - 115 = 421 |
Data interpretation questions often require calculating missing values based on the relationships between different data points presented in tables or charts. Key relationships in employee data typically include:
By using these relationships and any additional information provided in the question, you can deduce the missing values and answer the specific query.
The table shows District-wise data of a number of primary school teachers posted in schools of a city.
Study the table and answer the question:
District | Male teachers | Female teachers |
East | 1650 | 2375 |
North | 1075 | 2651 |
West | 1280 | 1520 |
South | 1170 | 1085 |
Central | 690 | 859 |
Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.
Source | Amit | Suresh | Nitin | Varun |
Salary | 35000 | 38500 | 29000 | 42000 |
Arrears | 6000 | 6300 | 5000 | 7500 |
Bonus | 1000 | 1100 | 1000 | 1240 |
Overtime | 1800 | 1950 | 1400 | 1500 |
Study the table and answer the question:
Income (Rs.) | No. of persons |
Less than 200 | 12 |
Less than 250 | 26 |
Less than 300 | 34 |
Less than 350 | 40 |
Less than 400 | 50 |
The following table shows the annual profit of a company (in Rs. lakh).
2014-2015 | 2015-2016 | 2016-0217 | 2017-2018 | 2018-2019 |
625 | 690 | 725 | 775 | 815 |
The period which has the maximum percentage increase in profit over the previous year is:
The table given below shows the number of persons participating in a survey from 6 different states.
| States | Persons |
| S1 | 100 |
| S2 | 200 |
| S3 | 400 |
| S4 | 500 |
| S5 | 600 |
| S6 | 800 |
What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?