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Question

If the matrix \( A = \begin{bmatrix} x & y \\ z & w \end{bmatrix} \) is skew symmetric, then which of the following is true? 

The correct answer is
x+w=0

Understanding Skew Symmetric Matrices

A matrix is called skew symmetric if its transpose equals its negative. For a matrix \( A \), this condition is represented as \( A^T = -A \). This property implies specific relationships between the elements of the matrix.

Applying the Skew Symmetric Condition to Matrix A

We are given the matrix \( A = \begin{bmatrix} x & y \\ z & w \end{bmatrix} \).

First, we find the transpose of A (\( A^T \)) by switching rows and columns:

$$ A^T = \begin{bmatrix} x & z \\ y & w \end{bmatrix} $$

Next, we find the negative of A (\( -A \)) by multiplying every element by -1:

$$ -A = \begin{bmatrix} -x & -y \\ -z & -w \end{bmatrix} $$

For A to be skew symmetric, \( A^T \) must equal \( -A \).

$$ \begin{bmatrix} x & z \\ y & w \end{bmatrix} = \begin{bmatrix} -x & -y \\ -z & -w \end{bmatrix} $$

Deriving Properties from Element Comparison

By comparing the elements in the same positions in both matrices, we get the following equations:

  • For the element in row 1, column 1: \( x = -x \)
  • For the element in row 1, column 2: \( z = -y \)
  • For the element in row 2, column 1: \( y = -z \)
  • For the element in row 2, column 2: \( w = -w \)

Solving these equations gives us:

  • From \( x = -x \), we have \( 2x = 0 \), which means \( x = 0 \).
  • From \( w = -w \), we have \( 2w = 0 \), which means \( w = 0 \).
  • The conditions \( z = -y \) and \( y = -z \) are equivalent and state that the off-diagonal elements are negatives of each other.

So, a skew-symmetric matrix of this form requires \( x = 0 \) and \( w = 0 \).

Evaluating the Given Options

Let's examine each option based on the derived conditions (\( x=0 \) and \( w=0 \)):

  • Option 1: \( x + w = 0 \)
    Substituting the values \( x=0 \) and \( w=0 \), we get \( 0 + 0 = 0 \). This statement is always true for a skew-symmetric matrix.
  • Option 2: \( x + z = 0 \)
    Substituting \( x=0 \), we get \( 0 + z = 0 \), meaning \( z = 0 \). This is only true if \( y \) is also 0, which isn't always the case.
  • Option 3: \( x - y = 0 \)
    Substituting \( x=0 \), we get \( 0 - y = 0 \), meaning \( y = 0 \). This is not necessarily true.
  • Option 4: \( y - z = 0 \)
    This implies \( y = z \). However, the condition is \( y = -z \). This equality only holds if \( y = z = 0 \), which is a specific case, not a general rule.

Final Conclusion on Skew Symmetric Property

The condition derived directly from the definition of a skew-symmetric matrix, specifically concerning the diagonal elements \( x \) and \( w \), is that they must both be zero. Therefore, the statement \( x + w = 0 \) must be true.

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Important Questions from Types of Matrices

  1. If \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} 1&1&{ - 1}\\ 2&{ - 3}&4\\ 3&{ - 2}&3 \end{array}} \right]{\rm{\;and\;\;B}} = \left[ {\begin{array}{*{20}{c}} { - 1}&{ - 2}&{ - 1}\\ 6&{12}&6\\ 5&{10}&5 \end{array}} \right]\) then which of the following is/are correct?

    1. A and B commute.

    2. AB is a null matrix.

    Select the correct answer using the code given below:
  2. Which one of the following matrices is an elementary matrix?

  3. The matrix  is \(\left[ {\begin{array}{c} 0&{ - 4 + i}\\ {4 + i}&0 \end{array}} \right]\)

  4. How many distinct matrices exist with all four entries taken from (1, 2)?

  5. If A and B are square matrices of order 2 such that det(AB) = det(BA), then which one of the following is correct?

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