This problem requires us to find the original principal sum. We are provided with the amount of interest earned during the second year and the annual interest rate, assuming the interest is compounded annually.
Here is the information given:
In compound interest, the interest earned each year is calculated on the accumulated amount from the previous year. The interest earned specifically *during* the second year is calculated on the total amount present at the end of the first year.
Let's follow these steps:
$ A_1 = P(1 + r) $
Using the given rate ($r = 0.05$):$ A_1 = P(1 + 0.05) = P(1.05) $
Interest for the 2nd year = $A_1 \times r$
By substituting the expression for $A_1$:Interest for the 2nd year = $ [P(1.05)] \times 0.05 $
$ [P(1.05)] \times 0.05 = 2352 $
$ P \times (1.05 \times 0.05) = 2352 $
$ P \times 0.0525 = 2352 $
To find P, divide 2352 by 0.0525:$ P = \frac{2352}{0.0525} $
It's helpful to convert the decimal $0.0525$ into a fraction, which is $\frac{525}{10000}$:$ P = \frac{2352}{\frac{525}{10000}} = \frac{2352 \times 10000}{525} $
Let's simplify this fraction. Divide both the numerator and the denominator by 25:$ P = \frac{2352 \times 400}{21} $
Now, perform the division of 2352 by 21:$ \frac{2352}{21} = 112 $
Finally, multiply the result by 400:$ P = 112 \times 400 $
$ P = 44800 $
Based on the calculations, the original principal sum is found to be ₹44,800.
A sum of ₹10,000 amounts to ₹12,321 in 2 years at a certain rate of interest per annum, compounded annually. The rate of interest per annum is:
If the interest earned during the $2^{nd}$ year on a certain sum is ₹3,342, and the rate of interest is 20% per annum compounded annually, then the sum is: