Compound interest is a powerful concept where the interest earned is added back to the principal amount, and then the new total earns interest. This means your money grows at an accelerating rate over time.
The formula for compound interest is given by:
$ A = P \left(1 + \frac{r}{n}\right)^{nt} $
Where:
For simplicity, if the interest is compounded annually, the formula becomes:
$ A = P(1 + r)^t $
Let's break down the problem step-by-step:
We are told that a sum of money triples itself in 11 years. Let the initial principal amount be P. After 11 years, the amount A becomes 3P.
Using the annual compound interest formula:
$ 3P = P(1 + r)^{11} $
Dividing both sides by P (assuming P is not zero), we get:
$ 3 = (1 + r)^{11} $
This equation gives us a relationship between the interest rate factor $(1+r)$ and the time.
We need to find the number of years (let's call it T) it will take for the sum to become 27 times the original principal amount (A = 27P).
Using the same formula:
$ 27P = P(1 + r)^T $
Dividing both sides by P:
$ 27 = (1 + r)^T $
We know that 27 can be expressed as a power of 3:
$ 27 = 3^3 $
From the first condition, we found that $3 = (1 + r)^{11}$. We can substitute this into the equation for 27:
$ 27 = \left[ (1 + r)^{11} \right]^3 $
Using the rule of exponents $(a^m)^n = a^{m \times n}$, we get:
$ 27 = (1 + r)^{11 \times 3} $
$ 27 = (1 + r)^{33} $
Now we have two equations for 27:
By comparing these two equations, we can see that the exponents must be equal:
$ T = 33 $
Therefore, it will take 33 years for the sum of money to amount to 27 times itself.
A sum of ₹10,000 amounts to ₹12,321 in 2 years at a certain rate of interest per annum, compounded annually. The rate of interest per annum is:
If the interest earned during the $2^{nd}$ year on a certain sum is ₹3,342, and the rate of interest is 20% per annum compounded annually, then the sum is: