If sin4α + 2cos4α - 1 = 0, where 0 ≤ α < π/2, then what is sin2α + cos2α equal to?
1
By solving the given equation, we find that sin2α + cos2α = 1. Hence, the correct answer is (b) 1.
Similar Questions
What is the value of sin 26° + sin 212° + sin 218° + … + sin 284° + sin 290°?
Consider the following statements:
1. (sec 2θ - 1) (1 - cosec 2θ) = 1
2. sin θ (1 + cos θ) -1 + (1 + cos θ) (sin θ) -1 = 2 cosec θ
Which of the above is/are correct?
Important Questions from Trigonometric Identities
If cos 2θ = sin θ and θ lies between 0 and 90°, then θ will be:
\(\frac{3 - 4\sin^2 \theta}{\cos^2 \theta} + 2\tan^2 \theta\) can be simplified as:
Simplify \( \left(\frac{1}{\sin^2 A} - 1\right) \), where \( 0 < A \leq 90^\circ \).
If \( \tan \theta = \frac{8}{15} \), then the value of \( \sqrt{\frac{1 - \sin \theta}{1 + \sin \theta}} \) is:
If the volume of a cuboid is \(3x^2 - 27\), then its possible dimensions are:
