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Question

If $r\sin\theta = \frac{7}{2}$ and $r\cos\theta = \frac{7\sqrt{3}}{2}$, then what will be the value of r?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
7

Finding the Value of $r$

We are given two equations:

  1. $r\sin\theta = \frac{7}{2}$
  2. $r\cos\theta = \frac{7\sqrt{3}}{2}$

To find the value of $r$, we can square both equations and add them together.

Step 1: Square the equations

Squaring the first equation:

$(r\sin\theta)^2 = \left(\frac{7}{2}\right)^2$ $r^2\sin^2\theta = \frac{49}{4}$

Squaring the second equation:

$(r\cos\theta)^2 = \left(\frac{7\sqrt{3}}{2}\right)^2$ $r^2\cos^2\theta = \frac{49 \times 3}{4} = \frac{147}{4}$

Step 2: Add the squared equations

Add the results from Step 1:

$r^2\sin^2\theta + r^2\cos^2\theta = \frac{49}{4} + \frac{147}{4}$

Step 3: Apply Trigonometric Identity

Factor out $r^2$ and use the identity $\sin^2\theta + \cos^2\theta = 1$:

$r^2(\sin^2\theta + \cos^2\theta) = \frac{49 + 147}{4}$ $r^2(1) = \frac{196}{4}$ $r^2 = 49$

Step 4: Solve for $r$

Take the square root of both sides. Since $r$ typically represents a distance or magnitude, we consider the positive root:

$r = \sqrt{49}$ $r = 7$

The value of $r$ is 7.

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