We are given two equations:
To find the value of $r$, we can square both equations and add them together.
Squaring the first equation:
$(r\sin\theta)^2 = \left(\frac{7}{2}\right)^2$ $r^2\sin^2\theta = \frac{49}{4}$Squaring the second equation:
$(r\cos\theta)^2 = \left(\frac{7\sqrt{3}}{2}\right)^2$ $r^2\cos^2\theta = \frac{49 \times 3}{4} = \frac{147}{4}$Add the results from Step 1:
$r^2\sin^2\theta + r^2\cos^2\theta = \frac{49}{4} + \frac{147}{4}$Factor out $r^2$ and use the identity $\sin^2\theta + \cos^2\theta = 1$:
$r^2(\sin^2\theta + \cos^2\theta) = \frac{49 + 147}{4}$ $r^2(1) = \frac{196}{4}$ $r^2 = 49$Take the square root of both sides. Since $r$ typically represents a distance or magnitude, we consider the positive root:
$r = \sqrt{49}$ $r = 7$The value of $r$ is 7.
The given equation can be reduced to
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If \(\sin θ = \frac{8}{{17}}\) , then find the value of tan θ.