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Question

If $p>q=p^2+q^3$ and $p<q=p^3-q^2$, then $(1>2)<3 = $

The correct answer is
720

The problem defines two operations based on conditions:

  • If $p > q$, then the operation (let's denote it by '>') results in $p^2 + q^3$.
  • If $p < q$, then the operation (let's denote it by '<') results in $p^3 - q^2$.

We need to evaluate the expression $(1>2)<3$. The notation suggests that the symbol used directly determines the formula applied, potentially irrespective of the condition check for the evaluation itself.

Evaluating $(1>2)$

In the expression $1>2$, the operator is '>'. We apply the formula associated with this operator:

Formula for '>': $p^2 + q^3$

Substitute $p=1$ and $q=2$: $1^2 + 2^3 = 1 + 8 = 9$

Let the result be $R = 9$.

Evaluating $R<3$

Now, we need to evaluate $R<3$, which is $9<3$. The operator is '<'. We apply the formula associated with this operator:

Formula for '<': $p^3 - q^2$

Substitute $p=9$ and $q=3$: $9^3 - 3^2 = 729 - 9 = 720$

Final Result

The value of the expression $(1>2)<3$ is 720.

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Important Questions from Algebra

  1. The difference between the two positive numbers x and y where x > y, is 25% of x. If the value of y is 15, then the value of x is:

  2. If p2 + q2 - r2 = 0, then the value of (p6 + q6 - r6) ÷ p2q2r2 is:

  3. If √2 + √x = √3, then the value of x is equal to:

  4. The sum of two numbers is 20 and their difference is 2.5. Ratio of these numbers will be:

  5. If \(\rm \frac{\sqrt{19 - x \sqrt{12}}}{1} = \sqrt 4 - \sqrt 3\)  then the value of x is equal to:

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