If $p>q=p^2+q^3$ and $p<q=p^3-q^2$, then $(1>2)<3 = $
The problem defines two operations based on conditions:
We need to evaluate the expression $(1>2)<3$. The notation suggests that the symbol used directly determines the formula applied, potentially irrespective of the condition check for the evaluation itself.
In the expression $1>2$, the operator is '>'. We apply the formula associated with this operator:
Formula for '>': $p^2 + q^3$
Substitute $p=1$ and $q=2$: $1^2 + 2^3 = 1 + 8 = 9$
Let the result be $R = 9$.
Now, we need to evaluate $R<3$, which is $9<3$. The operator is '<'. We apply the formula associated with this operator:
Formula for '<': $p^3 - q^2$
Substitute $p=9$ and $q=3$: $9^3 - 3^2 = 729 - 9 = 720$
The value of the expression $(1>2)<3$ is 720.
The difference between the two positive numbers x and y where x > y, is 25% of x. If the value of y is 15, then the value of x is:
If p2 + q2 - r2 = 0, then the value of (p6 + q6 - r6) ÷ p2q2r2 is:
If √2 + √x = √3, then the value of x is equal to:
The sum of two numbers is 20 and their difference is 2.5. Ratio of these numbers will be:
If \(\rm \frac{\sqrt{19 - x \sqrt{12}}}{1} = \sqrt 4 - \sqrt 3\) then the value of x is equal to: