If P, Q and R are three sets, then which of the following is correct?
P ∪ (Q ∩ R) = (P ∪ Q) ∩ (P ∪ R)
Set theory involves various operations that combine or compare sets. The most common set operations are union ($\cup$) and intersection ($\cap$). Understanding the properties and identities related to these operations is crucial for solving problems involving sets. These identities describe how sets behave under these operations, similar to how algebraic properties work with numbers.
There are several standard set properties or identities that govern how union and intersection interact. Some well-known identities include commutative, associative, and distributive laws.
These set properties help simplify complex expressions involving multiple set operations and multiple sets P, Q, and R.
We are looking for a correct identity among the given options involving sets P, Q, and R and the set operations union and intersection. Let's compare each option with the known set properties:
Comparing these with the distributive laws listed above:
Therefore, the only correct identity among the given options is the distributive law of union over intersection.
Based on the fundamental set properties, the equation $P \cup (Q \cap R) = (P \cup Q) \cap (P \cup R)$ represents a valid distributive law in set theory. This identity shows how the Union operation distributes over the Intersection operation when dealing with three sets P, Q, and R. Visualizing this with a Venn diagram can also help confirm this identity.
If A is an open set and B is a closed set, then B - A is
If A is a subset of B and B is a subset of C, then the cardinality of A ∪ B ∪ C is equal to:
Consider the following statements :
1. If f is the subset of Z × Z defined by f = {(xy, x − y); x, y ∈ Z}, then f is a function from Z to Z.
2. If f is the subset of N × N defined by f = {(xy, x + y); x, y ∈ N}, then f is a function from N to N.
Which of the statements given above is/are correct?
If P and Q be two sets such that P ∪ Q = P, then P ∩ Q will be
A set containing n elements, has exactly ..... subsets.