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Question

If P and Q be two sets such that P ∪ Q = P, then P ∩ Q will be

The correct answer is

Q

Understanding Set Operations and Set Theory: P and Q

This problem from Set Theory involves two sets, P and Q, and asks about their intersection based on a condition involving their union. We are given that for sets P and Q, the Set Union P \cup Q is equal to P.

The given condition illustrating a Set Relationship and Set Equality is: P \cup Q = P.

Analyzing the Set Union Condition: P ∪ Q = P

The Set Union of two sets, P \cup Q, contains all elements that are in P or in Q or in both. The condition P \cup Q = P signifies Set Equality, meaning every element from the combined sets P and Q is already contained within set P itself.

This can only be true if set Q does not contain any element that is not also in set P. In other words, every element of Q must also be an element of P. This is the definition of Subsets.

Thus, the condition P \cup Q = P is equivalent to stating that Q is a subset of P, denoted as Q \subseteq P.

Finding the Set Intersection: P ∩ Q

The Set Intersection of two sets, P \cap Q, consists of all elements that are common to both set P and set Q. Since we know from the given condition that Q \subseteq P, every element in Q is also in P.

Therefore, the elements that are common to both P and Q are exactly the elements that are in Q. The Set Intersection P \cap Q must contain all elements that belong to Q, and no other elements.

Hence, P \cap Q = Q.

Visualizing with a Venn Diagram

Imagine a Venn Diagram representing Set Operations for sets P and Q. The condition P \cup Q = P means the area covering both circles is just the area of the P circle. This graphically shows that the Q circle must be entirely inside the P circle, illustrating that Q is a subset of P.

If the Q circle is inside the P circle, the overlapping region (the intersection, P \cap Q) is simply the Q circle itself. This visualization confirms that P \cap Q = Q when Q is a subset of P.

Conclusion for P ∩ Q

When the union of sets P and Q results in P (i.e., P \cup Q = P), it establishes that Q is a subset of P. Consequently, the elements common to both sets, which form the set intersection P \cap Q, are precisely the elements of Q. Thus, P \cap Q = Q.

This is a key concept in Set Theory involving basic Set Operations and Set Relationships.

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Important Questions from Set Theory and types of Sets

  1. If A is an open set and B is a closed set, then B - A is

  2. A set containing n elements, has exactly ..... subsets.

  3. If P, Q and R are three sets, then which of the following is correct?

  4. Of the members of three athletic teams in a school, 21 are in the cricket team, 26 are in the hockey team and 29 are in the football team. Among them, 14 play hockey and cricket, 15 play hockey and football, 12 play football and cricket and 8 play all the three games. The total number of members in the three athletic teams is:

  5. The number of element in the power set P(S) of set S = {2, {1, 4}} is ?

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