If N = 13 and GROUP = 58, then which among the given options will MOBILE be equal to:
106
This question involves an alphabetic coding pattern where letters or words are assigned numerical values based on a specific rule. We are given two examples: N = 13 and GROUP = 58. We need to deduce the rule from these examples and apply it to find the value of MOBILE.
Let's consider the position of the letter 'N' in the English alphabet. The standard positions are A=1, B=2, ..., N=14, ..., Z=26. However, the given value for N is 13. This doesn't match the standard 1-based position (14) or a 0-based position (13). Let's think of other ways to assign numerical values to letters.
One common pattern is assigning values based on the position counting backward from Z. If we assign Z=1, Y=2, X=3, and so on, let's see what value N gets:
The position counting backward can be calculated as \(26 - (\text{standard position}) + 1\). The standard position of N is 14.
Value for N = \(26 - 14 + 1 = 12 + 1 = 13\).
This matches the given value N = 13. This suggests the coding pattern might be assigning a value to each letter based on its position when counting backward from Z, where Z=1.
Let's verify this pattern with the word GROUP. We will calculate the value for each letter in GROUP using the rule: Value = \(26 - (\text{standard position}) + 1\).
Now, let's sum the values for the letters in GROUP:
Total value for GROUP = Value(G) + Value(R) + Value(O) + Value(U) + Value(P)
Total value for GROUP = \(20 + 9 + 12 + 6 + 11 = 58\).
This calculated value 58 matches the given value for GROUP. The pattern is confirmed: Each letter's value is its position counting backward from Z=1, and the word's value is the sum of its letters' values.
| Letter | Standard Position (A=1) | Backward Position (Z=1) | Value |
|---|---|---|---|
| N | 14 | \(26 - 14 + 1 = 13\) | 13 |
| G | 7 | \(26 - 7 + 1 = 20\) | 20 |
| R | 18 | \(26 - 18 + 1 = 9\) | 9 |
| O | 15 | \(26 - 15 + 1 = 12\) | 12 |
| U | 21 | \(26 - 21 + 1 = 6\) | 6 |
| P | 16 | \(26 - 16 + 1 = 11\) | 11 |
Now, we apply the same pattern to the word MOBILE. We will find the backward position value for each letter:
Finally, we sum the values for the letters in MOBILE:
Total value for MOBILE = Value(M) + Value(O) + Value(B) + Value(I) + Value(L) + Value(E)
Total value for MOBILE = \(14 + 12 + 25 + 18 + 15 + 22\).
Let's add them up:
The total value for MOBILE is 106.
| Letter | Standard Position (A=1) | Backward Position (Z=1) | Value |
|---|---|---|---|
| M | 13 | \(26 - 13 + 1 = 14\) | 14 |
| O | 15 | \(26 - 15 + 1 = 12\) | 12 |
| B | 2 | \(26 - 2 + 1 = 25\) | 25 |
| I | 9 | \(26 - 9 + 1 = 18\) | 18 |
| L | 12 | \(26 - 12 + 1 = 15\) | 15 |
| E | 5 | \(26 - 5 + 1 = 22\) | 22 |
| MOBILE | 106 |
The calculated value for MOBILE is 106. Let's check the given options:
Our calculated value matches option 4.
The coding pattern used in this question assigns a value to each letter based on its reverse alphabetical order position (Z=1, Y=2, ... A=26). The value of a word is the sum of the values of its constituent letters.
Following this pattern:
| Concept | Explanation | Application in Question |
|---|---|---|
| Alphabet Position | Each letter has a standard position (A=1, B=2, ... Z=26). | Used to find the backward position. |
| Backward Alphabet Position | Position counting from Z=1 (Z=1, Y=2, ... A=26). Calculated as \(26 - \text{Standard Position} + 1\). | This is the value assigned to each letter. |
| Word Value | The sum of the values of the individual letters in the word. | Calculated for GROUP and MOBILE. |
Coding and decoding questions in reasoning tests often involve patterns related to alphabets and numbers. Here are some common types of patterns you might encounter:
Solving these questions requires careful observation of the given examples to identify the underlying rule or pattern. Practice with different types helps in quickly recognizing the logic.
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