Understanding the Encryption Logic

This question presents a simple letter-to-number substitution code. We are given the encrypted values for two words, 'Monday' and 'Belt', and need to use this information to find the encrypted value for 'Tombay'. The key is to identify the numerical value assigned to each unique letter present in the given words.

Decoding the Letter-to-Number Mapping

Let's analyze the given encryptions:

• The word ‘Monday’ is encrypted as 123456.
• The word ‘Belt’ is encrypted as 0789.

By comparing the letters in each word with the digits in their corresponding encrypted codes, we can deduce the following mapping:

We now have a mapping for all the letters present in 'Monday' and 'Belt'.

Encrypting the Word ‘Tombay’

The word we need to encrypt is ‘Tombay’. Let's take each letter of ‘Tombay’ and find its corresponding digit from the mapping we derived:

• The first letter is T. From our mapping, T corresponds to 9.
• The second letter is O. From our mapping, O corresponds to 2.
• The third letter is M. From our mapping, M corresponds to 1.
• The fourth letter is B. From our mapping, B corresponds to 0.
• The fifth letter is A. From our mapping, A corresponds to 5.
• The sixth letter is Y. From our mapping, Y corresponds to 6.

Putting these digits together in the correct sequence for ‘Tombay’ (T-O-M-B-A-Y), we get:

921056

Final Encrypted Code for Tombay

Based on the encryption logic derived from ‘Monday’ and ‘Belt’, the word ‘Tombay’ is encrypted as 921056.