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Question

The following table shows the percentage (%) distribution of teachers in six different universities A-F. Total number of teachers in university E is 1856. Based on the data in the table, answer the questions.

University -wise Distribution of Teachers

University Distribution ( %) of Teachers 
A11%
B17%
C19%
D6%
E29%
F18%

If L and M are the total number of teachers in Universities A, B and C together and Universities D, E and F together, respectively, then the value of M-L is exactly equal to the number of teachers in University ____.

The correct answer is

D

Understanding the Data Distribution

The question provides a table showing the percentage distribution of teachers across six universities (A, B, C, D, E, F). We are also given the exact number of teachers in University E, which is 1856. This information is key to finding the total number of teachers across all universities.

University Distribution (%) of Teachers
A 11%
B 17%
C 19%
D 6%
E 29%
F 18%

We are asked to find the difference (M-L), where L is the total number of teachers in Universities A, B, and C, and M is the total number of teachers in Universities D, E, and F. Finally, we need to identify which university has a number of teachers equal to this difference (M-L).

Calculating the Total Number of Teachers

The total number of teachers in University E is 1856, which represents 29% of the total teachers across all six universities. We can use this to find the total number of teachers.

Let the total number of teachers be $T$.

According to the data:

$\text{29% of } T = 1856$

$\frac{29}{100} \times T = 1856$

$T = \frac{1856 \times 100}{29}$

$T = 64 \times 100$

$T = 6400$

So, the total number of teachers in all six universities is 6400.

Calculating Teachers in Each University

Now we can calculate the number of teachers in each university using their respective percentages and the total number of teachers (6400).

  • Teachers in A = 11% of 6400 = $\frac{11}{100} \times 6400 = 11 \times 64 = 704$
  • Teachers in B = 17% of 6400 = $\frac{17}{100} \times 6400 = 17 \times 64 = 1088$
  • Teachers in C = 19% of 6400 = $\frac{19}{100} \times 6400 = 19 \times 64 = 1216$
  • Teachers in D = 6% of 6400 = $\frac{6}{100} \times 6400 = 6 \times 64 = 384$
  • Teachers in E = 29% of 6400 = $\frac{29}{100} \times 6400 = 29 \times 64 = 1856$ (Matches given data)
  • Teachers in F = 18% of 6400 = $\frac{18}{100} \times 6400 = 18 \times 64 = 1152$

Let's verify the total: $704 + 1088 + 1216 + 384 + 1856 + 1152 = 6400$. The individual calculations are correct.

Calculating L and M

L is the total number of teachers in Universities A, B, and C:

$L = \text{Teachers in A} + \text{Teachers in B} + \text{Teachers in C}$

$L = 704 + 1088 + 1216 = 3008$

M is the total number of teachers in Universities D, E, and F:

$M = \text{Teachers in D} + \text{Teachers in E} + \text{Teachers in F}$

$M = 384 + 1856 + 1152 = 3392$

Calculating M - L

Now, we find the difference M - L:

$M - L = 3392 - 3008$

$M - L = 384$

Identifying the University with M - L Teachers

We need to compare the value of M - L (384) with the number of teachers in each university:

  • Teachers in A: 704
  • Teachers in B: 1088
  • Teachers in C: 1216
  • Teachers in D: 384
  • Teachers in E: 1856
  • Teachers in F: 1152

The number of teachers equal to M - L (384) is found in University D.

Summary of Calculations

Entity Calculation Value
Total Teachers $(1856 / 29) \times 100$ 6400
Teachers in A $6400 \times 0.11$ 704
Teachers in B $6400 \times 0.17$ 1088
Teachers in C $6400 \times 0.19$ 1216
Teachers in D $6400 \times 0.06$ 384
Teachers in E $6400 \times 0.29$ 1856
Teachers in F $6400 \times 0.18$ 1152
L (A+B+C) $704 + 1088 + 1216$ 3008
M (D+E+F) $384 + 1856 + 1152$ 3392
M - L $3392 - 3008$ 384

The value of M - L is 384, which is exactly the number of teachers in University D.

Revision Table: Data Interpretation Practice

Concept Description Application in this problem
Percentage Distribution Showing how a total quantity is divided proportionally into categories. The table shows the percentage of total teachers in each university.
Finding Total from Percentage If a value represents a certain percentage of a total, the total can be found using the formula: Total = (Part / Percentage) * 100. Used the number of teachers in University E (1856) and its percentage (29%) to find the total number of teachers.
Calculating Part from Total and Percentage To find the value of a percentage of a total, use the formula: Part = Total * (Percentage / 100). Used the total teachers and each university's percentage to find the number of teachers in each university.
Summation Adding multiple values together. Used to calculate L (teachers in A+B+C) and M (teachers in D+E+F).
Difference Subtracting one value from another. Used to calculate M - L.

Additional Information: Data Interpretation Skills

Data interpretation questions often involve tables, charts, or graphs that represent data. The key skills required to solve such problems include:

  • Reading and Understanding Data: Carefully reading the table or chart to understand what the data represents and the units used.
  • Calculating Percentages: Understanding how to calculate percentages, percentage increases/decreases, and how to find a value given a percentage of a total.
  • Calculating Ratios and Proportions: Comparing quantities using ratios and solving for unknown values using proportions.
  • Averages: Calculating the average of a set of values.
  • Addition and Subtraction: Summing up values or finding the difference between them, as done in this problem to calculate L, M, and M-L.
  • Comparing Values: Comparing calculated values to determine relationships or find matches, as done here to find which university's teacher count equals M-L.

Practicing with different types of data representation (tables, bar graphs, pie charts, line graphs) helps improve data interpretation skills for exams.

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Important Questions from Tabulation

  1. The table shows District-wise data of a number of primary school teachers posted in schools of a city.

    Study the table and answer the question:

    District

    Male teachers

    Female teachers

    East

    1650

    2375

    North

    1075

    2651

    West

    1280

    1520

    South

    1170

    1085

    Central

    690

    859


    What is the difference between the total number of male teachers in the districts East, North, West taken together and the total number of female teachers in the districts East and South?
  2. Table shows income (in Rs. ) received by 4 employees of a company during the month of December 2020 and all their income sources.

    Source

    Amit

    Suresh

    Nitin

    Varun

    Salary

    35000

    38500

    29000

    42000

    Arrears

    6000

    6300

    5000

    7500

    Bonus

    1000

    1100

    1000

    1240

    Overtime

    1800

    1950

    1400

    1500


    What is the ratio of salary of Varun to his income other than salary?
  3. Study the table and answer the question:

    Income (Rs.)

    No. of persons

    Less than 200

    12

    Less than 250

    26

    Less than 300

    34

    Less than 350

    40

    Less than 400

    50


    What is the percentage of persons earning Rs. 250 or more?
  4. The following table shows the annual profit of a company (in Rs. lakh).

    2014-2015

    2015-2016

    2016-0217

    2017-2018

    2018-2019

    625

    690

    725

    775

    815

    The period which has the maximum percentage increase in profit over the previous year is:

  5. The table given below shows the number of persons participating in a survey from 6 different states.

    States Persons 
    S1100
    S2200 
    S3400 
    S4500 
    S5600 
    S6800

    What is the ratio of number of person participating in a survey from state S3 to the number of person participating in a survey from state S4?

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