This solution determines the expectation value of the operator $(L_+L_- + L_-L_+)$ in the quantum state $ |l = 1, m = 1\rangle $.
The operator $(L_+L_- + L_-L_+)$ is simplified using the identity relating it to the total angular momentum squared operator $L2$ and the z-component operator $Lz2$:
$ L_+L_- + L_-L_+ = 2(L^2 - L_z^2) $
We calculate the expectation value:
$ \langle l=1, m=1 | (L_+L_- + L_-L_+) | l=1, m=1 \rangle = \langle l=1, m=1 | 2(L^2 - L_z^2) | l=1, m=1 \rangle $
$ = 2 \left( \langle l=1, m=1 | L^2 | l=1, m=1 \rangle - \langle l=1, m=1 | L_z^2 | l=1, m=1 \rangle \right) $
The eigenvalues for $L2$ and $Lz2$ in a state $|l, m\rangle$ are:
For the state $|l = 1, m = 1\rangle$:
Substituting these values:
$ \text{Expectation Value} = 2 (2\hbar^2 - 1\hbar^2) = 2 (1\hbar^2) = 2\hbar^2 $
The expectation value is $2$ in units of $ \hbar^2 $.