For an electron in an atomic orbital, its angular momentum is described by quantum numbers.
The vector model describes the orientation of the orbital angular momentum vector ($\vec{L}$) relative to an external axis, typically the $z$-axis.
The angle $\theta$ between the orbital angular momentum vector $\vec{L}$ and the positive $z$-axis is determined by the quantum numbers $l$ and $m_l$ using the following relationship:
$ \cos \theta = \frac{m_l}{\sqrt{l(l+1)}} $
For a $2p$ electron, we have $l=1$. We need to find the minimum angle $\theta$ (in degrees, integer) relative to the positive $z$-axis. This occurs for the non-zero values of $m_l$. Let's calculate $\cos \theta$ for $m_l = +1$ and $m_l = -1$:
The value $m_l=0$ corresponds to $\cos \theta = 0$, which means $\theta = 90^\circ$. This is not the minimum angle.
To find the minimum angle $\theta$, we look at the possible values of $\cos \theta$. A smaller angle corresponds to a larger positive value of $\cos \theta$. Comparing $\frac{1}{\sqrt{2}}$ and $-\frac{1}{\sqrt{2}}$, the larger value is $\frac{1}{\sqrt{2}}$.
We find the angle $\theta$ corresponding to $\cos \theta = \frac{1}{\sqrt{2}}$:
$ \theta = \arccos\left(\frac{1}{\sqrt{2}}\right) $ $ \theta = 45^\circ $The minimum angle made by the orbital angular momentum vector and the positive $z$ axis for a $2p$ electron is $45^\circ$. Since the question asks for an integer value, the answer is 45.
An electron in the Coulomb field of a proton is in the following state of coherent superposition of orthonormal states $\psi_{nlm}$
$\Psi = \frac{1}{3}\psi_{100} + \frac{1}{\sqrt{3}}\psi_{210} - \frac{\sqrt{5}}{3}\psi_{320}$
Let $E_1, E_2$, and $E_3$ represent the first three energy levels of the system. A sequence of measurements is done on the same system at different times. Energy is measured first at time $t_1$ and the outcome is $E_2$. Then total angular momentum is measured at time $t_2 > t_1$ and finally energy is measured again at $t_3 > t_2$. The probability of finding the system in a state with energy $E_2$ after the final measurement is $P/9$. The value of $P$ is ______________ (in integer).
A particle has wavefunction
$\psi(x,y,z) = N ze^{-\alpha(x^2+y^2+z^2)}$,
where $N$ is a normalization constant and $\alpha$ is a positive constant. In this state, which one of the following options represents the eigenvalues of $L^2$ and $L_z$ respectively?
Some values of $Y_l^m$ are:
$Y_0^0 = \sqrt{\frac{1}{4\pi}}$, $Y_1^0 = \sqrt{\frac{3}{4\pi}} \cos\theta$, $Y_1^{\pm 1} = \mp \sqrt{\frac{3}{8\pi}} \sin\theta e^{\pm i\phi}$