If J = K in case of J – K flip-flop, then the resulting flip-flop is known as:
T FLIP-FLOP
A J-K flip-flop is a fundamental building block in sequential digital logic circuits. It has two inputs, labeled J and K, and typically two outputs, Q and its complement, Q'. The state of the flip-flop (the value of Q) changes based on the values of the J and K inputs at the triggering clock edge.
The standard operation modes for a J-K flip-flop are:
The question specifically asks about the scenario where the J and K inputs of a J-K flip-flop are made equal, meaning J = K.
Let's consider the two possible cases when J = K:
Now, let's compare this behavior to a T flip-flop (Toggle Flip-Flop). A T flip-flop has a single input, T.
By comparing the behavior when J = K in a J-K flip-flop with the behavior of a T flip-flop, we can see a direct correspondence:
| J Input | K Input | J-K Flip-Flop Next State (Q) | T Input | T Flip-Flop Next State (Q) |
|---|---|---|---|---|
| 0 | 0 | No Change (Hold) | 0 | No Change (Hold) |
| 1 | 1 | Toggle | 1 | Toggle |
As shown in the table, when J equals K, the J-K flip-flop exhibits the exact same functionality as a T flip-flop, where the common value of the J and K inputs acts as the T input.
Therefore, if J = K in a J-K flip-flop, the resulting flip-flop is functionally equivalent to a T Flip-Flop.
A master-slave flip flop has the characteristic that
Number of unused states in a 3-bit Johnson counter are:
In _________ sequential circuits, signals can affect the memory elements only at discrete instants of time.
Shifting the register content to left by two bits can be used to implement
How many Flip-Flops are required for mod-16 counter?