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Question

How many Flip-Flops are required for mod-16 counter?

The correct answer is

4

Flip-Flops for Mod-16 Counter

A mod-N counter, also known as a modulo-N counter, is a type of digital counter that counts through N distinct states before repeating its sequence. The "mod" in mod-N counter signifies the number of unique states the counter can achieve. For example, a mod-16 counter will count through 16 different states (from 0 to 15) and then reset back to 0 to start the count again.

Counter State Determination

The number of states a counter can represent is directly related to the number of flip-flops it uses. Each flip-flop in a digital circuit can store one bit of information, meaning it can be in one of two states: 0 or 1. If we have n number of flip-flops, the total number of unique states that can be represented by these flip-flops is calculated using the formula:

  • Total number of states \( = \text{2}^\text{n} \)

Where:

  • \(\text{n}\) represents the number of flip-flops used.

For a mod-N counter, the number of states N must be less than or equal to the maximum number of states that can be represented by the chosen number of flip-flops. Therefore, we need to find the smallest integer value of \(\text{n}\) such that:

  • \(\text{2}^\text{n} \ge \text{N}\)

Calculating Flip-Flops for Mod-16 Counter

In this question, we need to determine the number of flip-flops required for a mod-16 counter. Here, the number of distinct states (\(\text{N}\)) is 16. We need to find the smallest integer \(\text{n}\) such that \(\text{2}^\text{n}\) is greater than or equal to 16.

Let's evaluate the powers of 2:

  • If \(\text{n} = \text{1}\), then \(\text{2}^\text{1} = \text{2}\) (Not enough for 16 states)
  • If \(\text{n} = \text{2}\), then \(\text{2}^\text{2} = \text{4}\) (Not enough for 16 states)
  • If \(\text{n} = \text{3}\), then \(\text{2}^\text{3} = \text{8}\) (Not enough for 16 states)
  • If \(\text{n} = \text{4}\), then \(\text{2}^\text{4} = \text{16}\) (Exactly enough for 16 states)

Since \(\text{2}^\text{4} = \text{16}\), it means that 4 flip-flops can represent exactly 16 unique states (from 0000 to 1111 in binary). This makes 4 the minimum number of flip-flops required to construct a mod-16 counter.

Conclusion on Mod-16 Counter Design

To design a mod-16 counter, we need a sufficient number of memory elements (flip-flops) to store all 16 unique states. Based on our calculation, 4 flip-flops are precisely what is needed because they can generate \(2^4 = 16\) distinct output combinations. These flip-flops are connected in a specific configuration to create the desired counting sequence, forming a fundamental component in digital electronics and sequential circuits.

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Important Questions from Sequential Circuits

  1. A master-slave flip flop has the characteristic that

  2. Number of unused states in a 3-bit Johnson counter are:

  3. In _________ sequential circuits, signals can affect the memory elements only at discrete instants of time.

  4. Shifting the register content to left by two bits can be used to implement

  5. A 4-bit synchronous counter uses flip-flops with a propagation delay time of 15 ns each. The maximum possible time required for change of state will be

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