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Question

A 4-bit synchronous counter uses flip-flops with a propagation delay time of 15 ns each. The maximum possible time required for change of state will be

The correct answer is

15 ns

Synchronous Counter Basics

A synchronous counter is a type of digital counter where all the flip-flops are clocked simultaneously by a single common clock signal. This means that all flip-flops change their state at the same time, unlike asynchronous (ripple) counters where the output of one flip-flop acts as the clock for the next, leading to a ripple effect of state changes.

The key characteristic of synchronous counters is their parallel operation. When the common clock signal arrives, all flip-flops that are enabled to change state will do so nearly simultaneously.

Propagation Delay in Synchronous Counters

Propagation delay, often denoted as \( T_{pd} \), is the time it takes for the output of a logic gate or a flip-flop to respond to a change in its input. In the context of a flip-flop, it's the time delay between the active clock edge and the stable change at the output (Q or Q').

  • In a synchronous counter, because all flip-flops are triggered by the same clock edge at the same instant, their state changes occur in parallel.
  • The overall time required for the entire counter to change its state is determined by the propagation delay of a single flip-flop, as all changes are initiated simultaneously. There is no cumulative delay from one flip-flop affecting the clock of the next, as seen in asynchronous counters.
  • If there were different propagation delays for different flip-flops, the maximum time for the state change would be the delay of the flip-flop with the longest \( T_{pd} \). However, in this problem, all flip-flops have the same propagation delay.

Calculating Maximum Time for State Change

Given the problem, we have a 4-bit synchronous counter, and each flip-flop has a propagation delay time of 15 ns.

As explained, in a synchronous counter, all flip-flops are clocked in parallel. Therefore, the time it takes for the entire counter to transition from one state to the next is simply the propagation delay of one flip-flop.

Let \( T_{pd\_FF} \) be the propagation delay time of one flip-flop.

Given: \( T_{pd\_FF} = 15 \text{ ns} \)

For a synchronous counter, the maximum possible time required for the change of state (which is essentially the clock period's minimum requirement, or the total time for the output to stabilize after the clock edge) is:

Maximum time for change of state \( = T_{pd\_FF} \)

Maximum time for change of state \( = 15 \text{ ns} \)

This is because all flip-flops begin their transition at the same time upon the arrival of the clock pulse, and the state of the entire counter will be stable after the propagation delay of the individual flip-flops has passed.

Counter Type Clocking Mechanism Delay for N-bit Counter
Synchronous Counter All FFs clocked simultaneously by a common clock. \( T_{pd\_FF} \) (Single flip-flop delay)
Asynchronous (Ripple) Counter Output of one FF clocks the next FF. \( N \times T_{pd\_FF} \) (Cumulative delay)

Based on this, the maximum possible time required for the change of state in the 4-bit synchronous counter is 15 ns.

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Important Questions from Sequential Circuits

  1. A master-slave flip flop has the characteristic that

  2. Number of unused states in a 3-bit Johnson counter are:

  3. In _________ sequential circuits, signals can affect the memory elements only at discrete instants of time.

  4. Shifting the register content to left by two bits can be used to implement

  5. How many Flip-Flops are required for mod-16 counter?

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