If AT = 20 and BEG = 70, then BANK = _____ .
308
This question is an example of a letter coding or word coding problem. We are given a rule applied to two words, "AT" and "BEG", which converts them into numerical values, 20 and 70 respectively. Our task is to identify the underlying pattern or rule and then apply it to the word "BANK" to find its corresponding numerical value.
Let's look at the numerical values assigned to the letters in the English alphabet. A=1, B=2, C=3, ..., Z=26. We need to see how the letters in "AT" and "BEG" might be combined to get 20 and 70.
Let's consider possible operations on their alphabetical positions (1 and 20):
Let's test if the product pattern works for "BEG" as well.
Their alphabetical positions are 2, 5, and 7. Let's find their product:
Product: $2 \times 5 \times 7 = 10 \times 7 = 70$ (This also matches the given value!)
From the analysis of "AT" and "BEG", the pattern appears to be consistent: The numerical value assigned to a word is the product of the alphabetical positions of its letters.
Now, let's apply this pattern to the word "BANK" to find its numerical value.
The alphabetical positions of the letters in "BANK" are 2, 1, 14, and 11.
According to the pattern, the value of BANK is the product of these positions:
Value of BANK $= 2 \times 1 \times 14 \times 11$
Let's calculate the product:
$2 \times 1 = 2$
$2 \times 14 = 28$
$28 \times 11$
To calculate $28 \times 11$:
$28 \times 11 = 28 \times (10 + 1) = (28 \times 10) + (28 \times 1) = 280 + 28 = 308$
Thus, the numerical value for BANK is 308.
| Letter | Position |
|---|---|
| A | 1 |
| T | 20 |
| B | 2 |
| E | 5 |
| G | 7 |
| N | 14 |
| K | 11 |
| Word | Letter Positions | Calculation | Result |
|---|---|---|---|
| AT | 1, 20 | $1 \times 20$ | 20 |
| BEG | 2, 5, 7 | $2 \times 5 \times 7$ | 70 |
| BANK | 2, 1, 14, 11 | $2 \times 1 \times 14 \times 11$ | 308 |
Understanding the pattern is key in coding-decoding questions. Practicing different types helps.
| Pattern Type | Description | Example (A=1, B=2...) |
|---|---|---|
| Shift in position | Letters shifted by a fixed number | CAT $\rightarrow$ DBU (+1 shift) |
| Reverse alphabetical position | A=26, B=25, ... | A=26, Z=1 |
| Sum of positions | Sum of alphabetical positions | CAT $\rightarrow 3+1+20=24$ |
| Product of positions | Product of alphabetical positions | CAT $\rightarrow 3 \times 1 \times 20=60$ |
| Combination of operations | Using addition, subtraction, multiplication etc. | Maybe $2 \times (\text{Sum of positions})$ |
Alphabetical positions are fundamental to many coding-decoding problems. It's helpful to know the positions of letters or have a quick way to figure them out. Some people use mnemonics like E J O T Y (5, 10, 15, 20, 25) or C F I L O R U X (3, 6, 9, 12, 15, 18, 21, 24) to quickly recall positions.
These types of questions test your logical reasoning and pattern recognition skills, which are important for many competitive exams.
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