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Question

If A is an invertible skew-symmetric matrix, then A -1 is a:

The correct answer is

Skew-symmetric matrix.

Understanding Skew-Symmetric Matrix Properties

The question asks us to identify the type of matrix that results from the inverse of an invertible skew-symmetric matrix (A-1). Let's break down the properties involved.

What is a Skew-Symmetric Matrix?

A matrix 'A' is called skew-symmetric if its transpose is equal to its negative. Mathematically, this is represented as:

$$ A^T = -A $$

For a matrix A to be skew-symmetric, all its diagonal elements must be zero. For example:

$$ A = \begin{pmatrix} 0 & a & b \\ -a & 0 & c \\ -b & -c & 0 \end{pmatrix} $$

When you transpose this matrix, you swap rows and columns. Notice how each element $A_{ij}$ becomes $A_{ji}$, and because it's skew-symmetric, $A_{ji} = -A_{ij}$. This includes the diagonal elements where $A_{ii} = -A_{ii}$, which implies $2A_{ii} = 0$, so $A_{ii} = 0$.

What is an Invertible Matrix?

A square matrix is invertible if it has a multiplicative inverse, denoted as A-1. This means that when you multiply the matrix by its inverse, you get the identity matrix (I):

$$ A A^{-1} = A^{-1} A = I $$

An important condition for invertibility is that the determinant of the matrix must not be zero (det(A) ≠ 0).

Deriving the Nature of A-1

We are given that A is an invertible skew-symmetric matrix. We need to find the property of A-1.

  1. Start with the definition of a skew-symmetric matrix:

    $$ A^T = -A $$

  2. Consider the transpose of the inverse matrix, $(A^{-1})^T$. We know a property relating the transpose and inverse of a matrix:

    $$ (A^{-1})^T = (A^T)^{-1} $$

  3. Now substitute the skew-symmetric property ($A^T = -A$) into the equation from step 2:

    $$ (A^T)^{-1} = (-A)^{-1} $$

  4. We also know another property related to the inverse of a scalar multiple of a matrix: $(-A)^{-1} = -(A^{-1})$.

    Proof for this property: Consider the product $(-A) \times -(A^{-1}) = (-1)A \times (-1)A^{-1} = (-1)(-1) \times A A^{-1} = 1 \times I = I$. Since multiplying $-A$ by $-(A^{-1})$ gives the identity matrix, $-(A^{-1})$ is indeed the inverse of $-A$.

  5. Combine the results from step 3 and step 4:

    $$ (A^{-1})^T = -(A^{-1}) $$

This final equation, $(A^{-1})^T = -(A^{-1})$, is the definition of a skew-symmetric matrix. Therefore, if A is an invertible skew-symmetric matrix, its inverse, A-1, must also be skew-symmetric.

Conclusion

Based on the derivation, the inverse of an invertible skew-symmetric matrix is a skew-symmetric matrix.

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Important Questions from Types of Matrices

  1. If \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} 1&1&{ - 1}\\ 2&{ - 3}&4\\ 3&{ - 2}&3 \end{array}} \right]{\rm{\;and\;\;B}} = \left[ {\begin{array}{*{20}{c}} { - 1}&{ - 2}&{ - 1}\\ 6&{12}&6\\ 5&{10}&5 \end{array}} \right]\) then which of the following is/are correct?

    1. A and B commute.

    2. AB is a null matrix.

    Select the correct answer using the code given below:
  2. Which one of the following matrices is an elementary matrix?

  3. The matrix  is \(\left[ {\begin{array}{c} 0&{ - 4 + i}\\ {4 + i}&0 \end{array}} \right]\)

  4. How many distinct matrices exist with all four entries taken from (1, 2)?

  5. If A and B are square matrices of order 2 such that det(AB) = det(BA), then which one of the following is correct?

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